Rui Barradas
?s 20:45 de 12/02/21, robin hankin escreveu:
Rui
?> x <- array(runif(60), dim = c(10, 2, 3))
?> array(x[slice.index(x,1) %in% 1:5],c(5,dim(x)[-1]))
(I don't see this on stackoverflow; should I post this there too?)?
Most of the magic package is devoted to handling arrays of arbitrary
dimensions and this functionality might be good to include if anyone
would find it useful.
HTH
Robin
<mailto:hankin.robin at gmail.com>
On Sat, Feb 13, 2021 at 12:26 AM Rui Barradas <ruipbarradas at sapo.pt
<mailto:ruipbarradas at sapo.pt>> wrote:
??? Hello,
??? This came up in this StackOverflow post [1].
??? If x is an array with n dimensions, how to subset by just one
dimension?
??? If n is known, it's simple, add the required number of commas in
their
??? proper places.
??? But what if the user doesn't know the value of n?
??? The example below has n = 3, and subsets by the 1st dim. The
apply loop
??? solves the problem as expected but note that the index i has
??? length(i) > 1.
??? x <- array(1:60, dim = c(10, 2, 3))
??? d <- 1L
??? i <- 1:5
??? apply(x, MARGIN = -d, '[', i)
??? x[i, , ]
??? If length(i) == 1, argument drop = FALSE doesn't work as I
expected it
??? to work, only the other way does:
??? i <- 1L
??? apply(x, MARGIN = -d, '[', i, drop = FALSE)
??? x[i, , drop = FALSE]
??? What am I missing?
??? [1]
https://stackoverflow.com/questions/66168564/is-there-a-native-r-syntax-to-extract-rows-of-an-array
??? Thanks in advance,
??? Rui Barradas
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