Question about substitute() and function def

Hi,

Can someone help me understand why

  substitute(function(a) a + 1, list(a=quote(foo)))

gives

  function(a) foo + 1

and not

  function(foo) foo + 1

The man page leads me to believe this is related to lazy evaluation of
function arguments, but I'm not getting the big picture.

I think it's the same reason that this happens:

 > substitute(c( a = 1, b = a), list(a = quote(foo)))
c(a = 1, b = foo)

The "a" in function(a) is the name of the arg, it's not the arg itself 
(which is missing).  Now a harder question to answer is why this happens:

 > substitute(function(a=a) 1, list(a=quote(foo)))
function(a = a) 1

I would have expected to get "function(a = foo) 1".

Duncan Murdoch