round() ignores missing arguments if it is used inside another function where some arguments are missing.

On Fri, Nov 18, 2011 at 9:34 AM, Kevin R. Coombes
<kevin.r.coombes at gmail.com> wrote:

You can also see the odd behavior without wrapping round in another
function:

round(100.1, digits=)

[1] 100

Hmm... is there a reason for why the parser accepts that construct?

Some example:

parse(text="f(a=)")

expression(f(a=))

parse(text="f[a=]")

expression(f[a=])

parse(text="(a=)")

Error in parse.default(text = "(a=)") : <text>:1:4: unexpected ')'
1: (a=)

/Henrik

On 11/18/2011 10:19 AM, Joris Meys wrote:

On Fri, Nov 18, 2011 at 5:10 PM, Gavin Simpson<gavin.simpson at ucl.ac.uk>
 wrote:

round is indicated to not evaluate its arguments. I don't follow the C
code well enough to know if it should be catching the missing argument
further on - it must be because it is falling back to the default, but
the above explains that the not evaluating arguments is intended.

G

So if I understand it right, the y argument is not evaluated in the
fun2 function but deeper in the C code. that explains the lack of the
error message, thanks! I keep on learning every day.
Cheers

Joris