as.POSIXct behaviour

On 9 March 2017 at 01:29, Arunkumar Srinivasan

The time info is lost on the first index as well. And it happens *silently*.

Yes, because it assumes homogeneous format on the entire vector.  You
may want to
do  two passes with different formats or run a regular expression to
catch typos.

lapply(x, as.POSIXct)
A list is returned, but values are as I?d expect. Would it be possible
to retain the time info with as.POSIXct(x) directly as well? If not,

This behaves differently because you are running as.POSIXct for each element
separately.