Matrices given to pt? [was: [R] for loops and counters]
I think what is happening is that it is preserving attributes of the input. e.g.
x <- 1:3 attr(x, "A") <- 23 pt(x, 3)
[1] 0.8044989 0.9303370 0.9711656 attr(,"A") [1] 23 Note that attribute A was preserved. Since matrices are just vectors with a dim attribute that would imply the result. I agree that it would be a good idea to document it if it is intended.
On 7/15/06, Fran?ois Pinard <pinard at iro.umontreal.ca> wrote:
Hi, people. I was a bit intrigued by the message quoted below. Indeed, if pt() is given a matrix, it returns a matrix. Should this feature be documented? ?pt speaks about "a vector of quantiles", and says nothing about the type of what it returns. The same might presumably apply to other distribution-related functions. ----- Forwarded message from Martyn Plummer <plummer at iarc.fr> ----- From: Martyn Plummer <plummer at iarc.fr> Date: Thu Apr 10 10:07:01 2003 Subject: [R] for loops and counters Peter, You didn't say what goes wrong, but you mind find this version more useful tstat <- (matrix(means, k,k, byrow=TRUE) - matrix(means, k,k,byrow=FALSE))/rms pvalue <- 2*(1-pt(abs(tstat), df=df)) pvalue[upper.tri(pvalue)] S is designed to allow you to work with "whole objects", which means that for loops can (and should) be avoided. Martyn On 05-Oct-99 Peter B. Mandeville wrote:
I am trying to assign values to a vector (pvalue). Similar code works in C but not in R. What am I doing wrong?
r <- pvalue <- 0
for(i in (1:(k-1))){
for(j in (i+1):k){
r <- r+1
tstat <- (means[i]-means[j])/rms
pvalue[r] <- 2*(1-pt(abs(tstat),df))
}
}
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