pbinom with size argument 0 (PR#8560)
(Ted Harding) wrote:
On 03-Feb-06 Peter Dalgaard wrote:
(Ted Harding) <Ted.Harding at nessie.mcc.ac.uk> writes:
On 03-Feb-06 uht at dfu.min.dk wrote:
Full_Name: Uffe H?gsbro Thygesen Version: 2.2.0 OS: linux Submission from: (NULL) (130.226.135.250) Hello all. pbinom(q=0,size=0,prob=0.5) returns the value NaN. I had expected the result 1. In fact any value for q seems to give an NaN.
Well, "NaN" can make sense since "q=0" refers to a single sampled value, and there is no value which you can sample from "size=0"; i.e. sampling from "size=0" is a non-event. I think the probability of a non-event should be NaN, not 1! (But maybe others might argue that if you try to sample from an empty urn you necessarily get zero "successes", so p should be 1; but I would counter that you also necessarily get zero "failures" so q should be 1. I suppose it may be a matter of whether you regard the "r" of the binomial distribution as referring to the "identities" of the outcomes rather than to how many you get of a particular type. Hmmm.)
Note that dbinom(x=0,size=0,prob=0.5) returns the value 1.
That is probably because the .Internal code for pbinom may do a preliminary test for "x >= size". This also makes sense, for the cumulative p<dist> for any <dist> with a finite range, since the answer must then be 1 and a lot of computation would be saved (likewise returning 0 when x < 0). However, it would make even more sense to have a preceding test for "size<=0" and return NaN in that case since, for the same reasons as above, the result is the probability of a non-event.
Once you get your coffee, you'll likely realize that you got your p's and d's mixed up...
You're right about the mix-up! (I must mend the pipeline.)
I think Uffe is perfectly right: The result of zero experiments will be zero successes (and zero failures) with probability 1, so the cumulative distribution function is a step function with one step at zero ( == as.numeric(x>=0) ).
I'm perfectly happy with this argument so long as it leads to dbinom(x=0,size=0,prob=p)=1 and also pbinom(q=0,size=0,prob=p)=1 (which seems to be what you are arguing too). And I think there are no traps if p=0 or p=1.
(But it depends on your point of view, as above ... However, surely the two should be consistent with each other.)
Ted.
I prefer a (consistent) NaN. What happens to our notion of a Binomial RV as a sequence of Bernoulli RVs if we permit n=0? I have never seen (nor contemplated, I confess) the definition of a Bernoulli RV as anything other than some dichotomous-outcome one-trial random experiment. Not n trials, where n might equal zero, but _one_ trial. I can't see what would be gained by permitting a zero-trial experiment. If we assign probability 1 to each outcome, we have a problem with the sum of the probabilities. Peter Ehlers
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