bug in sum() on integer vector

Following this thread, I wondered why nobody tried cumsum to see where the integer
overflow occurs. On the shorter xx vector in the little script below I get a message:

Warning message:
Integer overflow in 'cumsum'; use 'cumsum(as.numeric(.))'

But sum() does not give such a warning, which I believe is the point of contention. Since
cumsum() does manage to give such a warning, and show where the overflow occurs, should
sum() not be able to do so? For the record, I don't class the non-zero answer as an error
in itself. I regard the failure to warn as the issue.

It (sum) does warn if you take the two "halves" separately. The issue is that the overflow is detected at the end of the summation, when the result is to be saved to an integer (which of course happens for all intermediate sums in cumsum)

x <- c(rep(1800000003L, 10000000), -rep(1200000002L, 15000000))
sum(x[1:10000000])

[1] NA
Warning message:
In sum(x[1:1e+07]) : Integer overflow - use sum(as.numeric(.))

sum(x[10000001:25000000])

[1] NA
Warning message:
In sum(x[10000001:1.5e+07]) : Integer overflow - use sum(as.numeric(.))

sum(x)

[1] 4996000

There's a pretty easy fix, essentially to move

    if(s > INT_MAX || s < R_INT_MIN){
        warningcall(call, _("Integer overflow - use sum(as.numeric(.))"));
        *value = NA_INTEGER;
    }

inside the summation loop. Obviously, there's a speed penalty from two FP comparisons per element, but I wouldn't know whether it matters in practice for anyone.

Peter Dalgaard, Professor
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd.mes at cbs.dk  Priv: PDalgd at gmail.com