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Wish: keep names in mapply() result

3 messages · Gregor Gorjanc, Charles C. Berry

#
Hello!

I have noticed that mapply() drops names in R 2.3.1 as well as in
r-devel. Here is a simple example:

l <- list(a=1, b=2)
k <- list(1)
mapply(FUN="+", l, k)
[1] 2 3
mapply(FUN="+", l, k, SIMPLIFY=FALSE)
[[1]]
[1] 2

[[2]]
[1] 3

Help page does not indicate that this should happen. Argument USE.NAMES
does not have any effect here as it used only in a bit special
situation: "If the first ... argument is character and the result does
not already have names, use it as the names." But result is always
without names as shown above. Did I miss any peculiarities?

This is not consistent with lapply, which keeps names i.e.

lapply(l, "+", 1)
$a
[1] 2

$b
[1] 3

I have attached and copied (at the end) patch proposal against SVN that
adds names back to the result if x had it (only R as my C is ...). This
way it would also be consistent with lapply. make check-all seems to be
happy with changes. Now we get:

mapply(FUN="+", l, k)
a b
2 3

mapply(FUN="+", l, k, SIMPLIFY=FALSE)
$a
[1] 2

$b
[1] 3

And if we had "character" (with some variations) for first ... then:

l <- list(a="1", b="2")
mapply(FUN="paste", l, k)
    a     b
"1 1" "2 1"

l <- list("1", "2")
mapply(FUN="paste", l, k)
[1] "1 1" "2 1"

l <- c("1", "2")
mapply(FUN="paste", l, k)
    1     2
"1 1" "2 1"

Index: src/library/base/R/mapply.R
===================================================================
--- src/library/base/R/mapply.R (revision 39024)
+++ src/library/base/R/mapply.R (working copy)
@@ -3,8 +3,16 @@
     FUN <- match.fun(FUN)
     dots <- list(...)

+    if(!is.null(names(dots[[1]]))) {
+        isNamed <- TRUE
+        namesX <- names(dots[[1]])
+    } else {
+        isNamed <- FALSE
+    }
+
     answer<-.Call("do_mapply", FUN, dots, MoreArgs, environment(),
                   PACKAGE="base")
+    if(isNamed) names(answer) <- namesX

     if (USE.NAMES && length(dots) && is.character(dots[[1]]) &&
         is.null(names(answer))) names(answer) <- dots[[1]]
@@ -47,4 +55,4 @@
     }
     formals(FUNV) <- formals(FUN)
     FUNV
-}
\ No newline at end of file
+}
#
Gregor:

Works for me on 2.3.0:
a     b     c     d     e 
"A 1" "B 2" "C 3" "D 4" "E 5"
a       b       c       d       e 
"a A 1" "b B 2" "c C 3" "d D 4" "e E 5"
but  this does not yield names:
[1] "a A 1" "b B 2" "c C 3" "d D 4" "e E 5"


Perhaps the help page would be clearer if it said:

USE.NAMES: If the first ... argument is a character ***vector*** and the result
           doesn't already have names, use it as the names


Chuck
On Thu, 31 Aug 2006, Gregor Gorjanc wrote:

            
Charles C. Berry                        (858) 534-2098
                                          Dept of Family/Preventive Medicine
E mailto:cberry at tajo.ucsd.edu	         UC San Diego
http://biostat.ucsd.edu/~cberry/         La Jolla, San Diego 92093-0717
#
Hello,

Charles Berry sent me (off-list) his proposal, which I find better
(after slight modification) than mine. I would say that proposed changes
make mapply even more consistent with (some) *apply* funcs in terms of
names. Patches to mapply.R and mapply.Rd are attached. I have runned
make check-all and it seems that there are no problems with this change.
I hope R core will find this worth to apply.

New behaviour without first ... as character:

l <- list(a=1, b=2)
k <- list(1)
mapply(FUN="+", l, k)
a b
2 3

mapply(FUN="+", l, k, USE.NAMES=FALSE)
[1] 2 3

mapply(FUN="+", l, k, SIMPLIFY=FALSE)
$a
[1] 2

$b
[1] 3

mapply(FUN="+", l, k, SIMPLIFY=FALSE, USE.NAMES=FALSE)
[[1]]
[1] 2

[[2]]
[1] 3

New behaviour with first ... as character _with_ names:

l <- c("1", "2")
names(l) <- c("a", "b")
mapply(FUN="paste", l, k)
    a     b
"1 1" "2 1"

mapply(FUN="paste", l, k, USE.NAMES=FALSE)
[1] "1 1" "2 1"

mapply(FUN="paste", l, k, SIMPLIFY=FALSE)
$a
[1] "1 1"

$b
[1] "2 1"

mapply(FUN="paste", l, k, SIMPLIFY=FALSE, USE.NAMES=FALSE)
[[1]]
[1] "1 1"

[[2]]
[1] "2 1"

New behaviour with first ... as character _without_ names:

l <- c("1", "2")
mapply(FUN="paste", l, k)
    1     2
"1 1" "2 1"

mapply(FUN="paste", l, k, USE.NAMES=FALSE)
[1] "1 1" "2 1"

mapply(FUN="paste", l, k, SIMPLIFY=FALSE)
$`1`
[1] "1 1"

$`2`
[1] "2 1"

mapply(FUN="paste", l, k, SIMPLIFY=FALSE, USE.NAMES=FALSE)
[[1]]
[1] "1 1"

[[2]]
[1] "2 1"

Regards, Gregor
Gregor Gorjanc wrote:
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