The documentation of seq() states that any one-parameter call to
seq(one.parameter) is interpreted as an along= parameter. Hoewever, if one.parameter is
a vector of length 1, one.parameter is obviously interpreted as a length=
argument, see example below. This behaviour probably cannot be changed and is
the same with the prototype, however, the exception should be documented at
least.
\note{ Attention: if seq is called with one unnamed parameter like in
\code{seq(a)} AND the parameter is a vector of length 1, this parameter will NOT be
interpreted as an along= argument but as an length= argument. Try \code{for
(len in 0:10)print(seq(seq(20, length=len)))} to see this exception and
\code{for (len in 0:10)print(seq(along=seq(20, length=len)))} to avoid the
exception. As a consequence, programmers are encouraged to always name a single
parameter as in \code{seq(along=a)} }
Best
Jens Oehlschlägel
for (len in 0:10)print(seq(seq(20, length=len)))
numeric(0) [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 [1] 1 2 [1] 1 2 3 [1] 1 2 3 4 [1] 1 2 3 4 5 [1] 1 2 3 4 5 6 [1] 1 2 3 4 5 6 7 [1] 1 2 3 4 5 6 7 8 [1] 1 2 3 4 5 6 7 8 9 [1] 1 2 3 4 5 6 7 8 9 10
for (len in 0:10)print(seq(along=seq(20, length=len)))
numeric(0) [1] 1 [1] 1 2 [1] 1 2 3 [1] 1 2 3 4 [1] 1 2 3 4 5 [1] 1 2 3 4 5 6 [1] 1 2 3 4 5 6 7 [1] 1 2 3 4 5 6 7 8 [1] 1 2 3 4 5 6 7 8 9 [1] 1 2 3 4 5 6 7 8 9 10
version
_ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 6.2 year 2003 month 01 day 10 language R
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