0/1 vector for indexing leads to funny behaviour (PR#8389) (maybe a documentation deficiency?)

Yes, 0/1 (numeric) are intended to be used as index vectors -- and they
have the semantics of numeric indices, which is that 0 elements in the
index are omitted from the result.  This can be a very useful mode of
operation in many situations.

I was going to write "This is described in both the introduction to R,
and in the documentation for '['", except that I checked before I wrote
and was surprised to be unable to any discussion of zeros in indexing in
any of the first three places I looked:

(1) help page for '[' (There is discussion of zero indices here, but
only in the context of using matrices to index matrices, not in the
context of ordinary vector indices).

(2) Section 2.7 "Index vectors: selecting and modifying subsets of a
data set" in "An Introduction to R", which does say this about numeric
indices:
    2. A vector of positive integral quantities. In
       this case the values in the index vector must
       lie in the set {1, 2, . . . , length(x)}
(This seems to commit the sin of not telling the whole truth.)

(3) Section 5.5 "Array Indexing.  Subsections of an array" (In "An
Introduction to R")

Question for others: did I miss something obvious, or is this a
documentation deficiency that zeros in indices are not discussed in 3 of
some obvious first places to look?

If indeed this is a documentation deficiency, I'm happy to contribute
documentation patch, but I await other opinions before spending any time
on that.

-- Tony Plate

rasche at molgen.mpg.de wrote:

Full_Name: Axel Rasche
Version: 2.2.0
OS: Linux
Submission from: (NULL) (141.14.21.81)


Dear Debuggers,

This is not a serious problem. Are 0/1 vectors intended to be used as i=

vectors? If yes, there is a bug. If not, it leads just to some funny be=

rather than an error message.

In the appendix is some simple code to reproduce the problem. A logical=

as.logic(a) helps by indexing the vector b. The 0/1 vector a just retur=

first value "a". But as many times as there is a 1 in a.

Best regards,
Axel


Appendix:

b =3D c("a","b","c","d")
a =3D c(0,1,1,0)
b[as.logical(a)]
b[a]
a =3D c(1,0,1,0)
b[as.logical(a)]
b[a]
a =3D c(0,1,1,1)
b[as.logical(a)]
b[a]