2 factor split and lapply
HI, I think this will be more appropriate. dcast(testframe,factor2~factor1,value.var="data",mean) ? factor2??? a?? b 1?????? 1 3.34 NaN 2?????? 2 2.10 4.2 A.K.
On Monday, December 23, 2013 9:37 AM, arun <smartpink111 at yahoo.com> wrote:
Hi, You could try: library(reshape2) dcast(as.data.frame(as.table(by(testframe[,3],testframe[,-3],mean))),factor2~factor1,value.var="Freq") #? factor2??? a?? b #1?????? 1 3.34? NA #2?????? 2 2.10 4.2 A.K.
On Monday, December 23, 2013 9:24 AM, Onur Uncu <onuruncu at gmail.com> wrote:
Sure, here is a reproducible example:
testframe<-data.frame(factor1=c("a","b","a"),factor2=c(1,2,2),data=c(3.34,4.2,2.1))
splitframe<-split(testframe,list(factor1=testframe$factor1,factor2=testframe$factor2))
lapply(splitframe,function(x)mean(x[,"data"]))
The above lapply returns
$a.1
[1] 3.34
$b.1
[1] NaN
$a.2
[1] 2.1
$b.2
[1] 4.2
The results are correct but not presented in a format I prefer... Factor1 and factor2 are combined into a single factor, which is not desired. I want to keep them seperate. Ideally, a table output as below.
? ?? a? ? ? ? ? b
1?? 3.34? ?? NaN
2?? 2.1? ? ?? 4.2
How can I achieve this please?
On 23 Dec 2013, at 00:44, Bert Gunter <gunter.berton at gene.com> wrote: I believe you missed ?tapply which does what you want I think (in the absence of a reproducible example one cannot be sure). Cheers, Bert Bert Gunter Genentech Nonclinical Biostatistics (650) 467-7374 "Data is not information. Information is not knowledge. And knowledge is certainly not wisdom." H. Gilbert Welch
On Sun, Dec 22, 2013 at 3:54 PM, Onur Uncu <onuruncu at gmail.com> wrote: R Users, I have a data frame which I split using 2 factors using the split function: split(datframe, list(f=factor1, f2=factor2)); I then used lapply to get some summary statistics grouped by factor1 and factor2. I now want to change the appearance of this output. I want to get? a 2 dimensional table where columns represent values of factor1, rows represent values of factor2 and the entries on the table represent the summary results that were calculated by lapply. I tried as.table() function but did not help. It seems the problem is that R combined factor1 and factor 2 into one factor when I used list(f=factor1, f2=factor2) in the split function. So R is now unable to treat them as 2 different factors in order to put them on row and columns of a table... Any ideas how I can achieve the desired table? Thanks for your help. ? ? ? ? [[alternative HTML version deleted]]
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______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.