find closest value in a vector based on another vector values
Jorge: No.
a <-c(1,5,8,15,32,33.5,69) b <-c(8.5,33) a[findInterval(b, a)]
[1] 8 32 ##should be 8 33.5 I believe it has to be done explicitly by finding all the differences and choosing those n with minimum values, depending on what n you want. Note that the problem is incompletely specified. What if the same value of a is closest to several values of b? -- do you want all the values you choose to be different or not, in which case they may not be minimum? a <- c(1, 8, 9) b <- c(2,3) Then what are the 2 closest values of a to b? -- Bert
On Tue, Jun 18, 2013 at 5:43 AM, Jorge I Velez <jorgeivanvelez at gmail.com> wrote:
Dear Andras, Try
a[findInterval(b, a)]
[1] 8 32 HTH, Jorge.- On Tue, Jun 18, 2013 at 10:34 PM, Andras Farkas <motyocska at yahoo.com> wrote:
Dear All, would you please provide your thoughts on the following: let us say I have: a <-c(1,5,8,15,32,69) b <-c(8.5,33) and I would like to extract from "a" the two values that are closest to the values in "b", where the length of this vectors may change but b will allways be shorter than "a". So at the end based on this example I should have the result "f" as f <-c(8,32) appreciate the help, Andras
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______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Bert Gunter Genentech Nonclinical Biostatistics Internal Contact Info: Phone: 467-7374 Website: http://pharmadevelopment.roche.com/index/pdb/pdb-functional-groups/pdb-biostatistics/pdb-ncb-home.htm