Message-ID: <644e1f320911050732v7d7ad4bbwf19b6c804129b509@mail.gmail.com>
Date: 2009-11-05T15:32:21Z
From: jim holtman
Subject: How to refer to the last a few rows?
In-Reply-To: <366c6f340911050617i5b2b833l9a109b0ad7b7ce56@mail.gmail.com>
With the flexibility of R, you can always create a function that will
allow you to avoid retyping.
On Thu, Nov 5, 2009 at 9:17 AM, Peng Yu <pengyu.ut at gmail.com> wrote:
> On Thu, Nov 5, 2009 at 7:24 AM, jim holtman <jholtman at gmail.com> wrote:
>> will this do:
>>
>>> x
>> ? ? [,1] [,2] [,3] [,4] [,5]
>> [1,] ? ?1 ? ?6 ? 11 ? 16 ? 21
>> [2,] ? ?2 ? ?7 ? 12 ? 17 ? 22
>> [3,] ? ?3 ? ?8 ? 13 ? 18 ? 23
>> [4,] ? ?4 ? ?9 ? 14 ? 19 ? 24
>> [5,] ? ?5 ? 10 ? 15 ? 20 ? 25
>>> tail(x[,tail(seq(ncol(x),3))], 2)
>> ? ? [,1] [,2] [,3]
>> [4,] ? 24 ? 19 ? 14
>> [5,] ? 25 ? 20 ? 15
>>>
>
> I would avoid to type the variable name twice. Because this is very
> inconvenient when the variable name is long.
>
> a_loooooooooooooooooong_expression_or_variable[nrow(a_loooooooooooooooooong_expression_or_variable),]
>
> BTW, you misunderstood my question. My question was whether is a
> better way to get the last a few columns than 't(tail(t(x),2))'.
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?