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Best way to turn a list into a data.frame

On Mon, Apr 6, 2009 at 8:49 AM, Daniel Brewer <daniel.brewer at icr.ac.uk> wrote:
l <- list("3845" = c("a", "b", "c"), "1029" = c("d", "e","f"))

libary(reshape)
melt(l)

Hadley