Cannot get "==" operator to return TRUE
On 12-02-03 11:10 AM, G See wrote:
Sorry, I meant Do you know of a way to print a string such that I can see whether it contains a *space* or a no-break space?
Use tools::showNonASCII(x). On Petr's example, it gives 1: n/a<c2><a0> Duncan Murdoch
On Fri, Feb 3, 2012 at 10:10 AM, G See<gsee000 at gmail.com> wrote:
Petr, Thank you! That is great. Do you know of a way to print a string such that I can see whether it contains a string or a no-break space? Thanks, Garrett On Fri, Feb 3, 2012 at 10:01 AM, Petr Savicky<savicky at cs.cas.cz> wrote:
On Fri, Feb 03, 2012 at 09:25:10AM -0600, G See wrote:
I have a data.frame named "df". The dput of df is at the bottom of this e-mail. What I'd like to do is replace the "n/a " values with NA. On Mac OSX, it works to do this: df[df == "n/a"]<- NA However, it does not work on Ubuntu. See below. Thanks in advance, Garrett
x<- df[27, 4] # complete data.frame dput is below dput(x)
"n/a "
Hi. This string contains a no-break space, not a space. "n/a " == "n/a\uA0" [1] TRUE "n/a\uA0" [1] "n/a " Hope this helps. Petr Savicky.
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