Split String in regex while Keeping Delimiter

On Wed, 12 Apr 2023 08:29:50 +0000

Some example data:
?leucocyten + gramnegatieve staven +++ grampositieve staven ++?
?leucocyten ? grampositieve coccen +?
?
I want to split the strings such that I get the following result:
c(?leucocyten +?, ??gramnegatieve staven +++?,
??grampositieve staven ++?)
c(?leucocyten ??, ?grampositieve coccen +?)
?
I have tried strsplit with a regular expression with a positive
lookahead, but I am not able to achieve the results that I want.

It sounds like you need positive look-behind, not look-ahead: split on
spaces only if they _follow_ one to three of '+' or '-'. Unfortunately,
repetition quantifiers like {n,m} or + are not directly supported in
look-behind expressions (nor in Perl itself). As a special case, you
can use \K, where anything to the left of \K is a zero-width positive
match:

x <- c(
 'leucocyten + gramnegatieve staven +++ grampositieve staven ++',
 'leucocyten - grampositieve coccen +'
)
strsplit(x, '[+-]{1,3}+\\K ', perl = TRUE)
# [[1]]
# [1] "leucocyten +"             "gramnegatieve staven +++"
#     "grampositieve staven ++" 
# 
# [[2]]
# [1] "leucocyten -"           "grampositieve coccen +"

Best regards,
Ivan

P.S. It looks like your e-mail client has transformed every quote
character into typographically-correct Unicode quotes ?? and every
minus into an en dash, which makes it slightly harder to work with your
code, since typographically correct Unicode quotes are not R string
delimiters. Is it really ? that you'd like to split upon, or is it -?