[FORGED] IF LOOOP

On Jun 13, 2017, at 4:10 PM, Rolf Turner <r.turner at auckland.ac.nz> wrote:

On 14/06/17 08:46, matthias worni wrote:

Hey
This should be a rather simple quesiton for some of you. I want to make
some progress in looping...
I have the vector r, which contains single values --> see below:
r
  [1] 1.1717118 1.1605215 1.1522907 1.1422830 1.1065277 1.1165451 1.1163768
1.1048872 1.0848836 1.0627211
 [11] 1.0300964 1.0296879 1.0308194 1.0518188 1.0657229 1.0685514 1.0914881
1.1042577 1.1039351 1.0880163
I would like to take out simply the value "0.990956" from the vector,
printing out the rest of it.  The code is from the internet but does not
seem to work for my vector.

I'm not sure that the source of this code should be considered a trusted foundation for learning R. You should not be using for-loops to modify vectors in this manner.

Can't figure out why... Thanks for the help
r <- as.vector(lw)

That's probably not needed.

count=0
for (i in r)  {
  if(i == 0.990956) {
    break

I suspect you meant to use:

?'next'   # since `break` completely terminates a for-loop.


The ?'help' page has all the "control structures": `for`, `repeat`, `while` and associated boundaries and terminators

Both `break` and `next` are reserved words (names of functions, control tokens), so using the `?` operator requires quoting.

Also that for-next loop would do _nothing_ to the value of r. Printing would not modify the value of `r`.

You should read:

?Reserved

?'for'  # since `for` is also reserved

?print

  }
    print(i)
  }

FAQ 7.31

After following Rolf's advice ... Try:

r[ all.equal(r, 0.990956) ]

cheers,

Rolf Turner

Further note to matthias:
All caps in Subject is considered poor form, as is posting in HTML.

David Winsemius
Alameda, CA, USA