Odp: If help
Hi I would make an interaction of those two vectors. interaction(sample(letters[1:2], 20, replace=T),sample(letters[1:2], 20, replace=T)) [1] a.a a.b b.b b.a b.b b.b a.a a.a b.b b.a a.a a.a b.b b.a a.a a.b b.a a.a b.b [20] a.b Levels: a.a b.a a.b b.b You will get factor and you can change easily labels and change them to numeric vector. See, ?levels, ?factor Regards Petr r-help-bounces at r-project.org napsal dne 20.07.2010 19:14:28:
Hi Y'all, I have some data in a table with 2 columns. There are two values:
"Reduction"
and "No Reduction. " I am trying to make a new variable change which
recode
the combinations from column 1 and 2 into a single number. Here is a
snippet
from the table: [1,] "NoReduction" "NoReduction" [2,] "Reduction" "Reduction" [3,] "NoReduction" "NoReduction" [4,] "NoReduction" "NoReduction" [5,] "Reduction" "Reduction" [6,] "Reduction" "Reduction" [7,] "Reduction" "Reduction" [8,] "NoReduction" "NoReduction" [9,] "NoReduction" "NoReduction" [10,] "NoReduction" "NoReduction" This is the code that I have written so far.. for (i in 1:nrow(change20082009)) if(change20082009[i,1]=='No Reduction' & change20082009[i,2]=='No
Reduction')
"){change20082009[i,3] <- 1} else
if(change20082009[i,1]=='No Reduction' &
change20082009[i,2]=='Reduction')
{change20082009[i,3] <- -1} else
if(change20082009[i,1]=='Reduction' & change20082009[i,2]=='No
Reduction')
{change20082009[i,3] <- 2} else
if(change20082009[i,1]=='Reduction' &
change20082009[i,2]=='Reduction')
{change20082009[i,3] <- 0}
)
I can't seem to get the code above to work..Any suggestions (I am sure
it is
really basic)? Is there a better way to do this? Sincerely, tom [[alternative HTML version deleted]]
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