macro in a loop
COnsider the use of a 'list':
dataYear <- lapply(c(1940, 1950, 1960), function(.file){
read.table(paste("c:/data/", .file, '.csv', sep=''), header=TRUE, sep=',')
})
The you can access your data:
dataYear[['1940']]
or
dataYear$"1940"
On Sat, Mar 21, 2009 at 3:53 PM, Le Wang <ruser.le at gmail.com> wrote:
Hi there,
Thanks for your time in advance.
I am trying to read in multiple files. For example,
?data.1940 <- read.table("c:/data/1940.csv",header=TRUE,sep=",")
?data.1950 <- read.table("c:/data/1950.csv",header=TRUE,sep=",")
?data.1960 <- read.table("c:/data/1960.csv",header=TRUE,sep=",")
How can I write a loop to read the data? I was trying to use the following
? ? ? ?year<-c(1940,1950,1960)
? ? ? ?for (j in 1:3){
? ? ? ? ? ? ? ? ? ? ?data.year[j] <- read.table("c:/data/year[j]
.csv",header=TRUE,sep=",")
? ? ? ?}
But it is obviously wrong, as the marco is not proctected.
I have been googling around for a while but haven't succeeded in
finding any solutions. Thanks again for your help.
Le
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