Message-ID: <1302450490629-3439959.post@n4.nabble.com>
Date: 2011-04-10T15:48:10Z
From: Berend Hasselman
Subject: howto calculate column means in data frame
In-Reply-To: <9C2B89830110BF4A845878D9A31F3D925AE8229B62@UEAEXCHMBX.UEA.AC.UK>
jamaas wrote:
>
> Long story short, I have a big iterative procedure that produces a long
> list of data.frames such as the one called
> "results" here. Is there an easy way to produce a similar list of
> data.frames comprised of the mean of each of the
> columns in results, such that it ends up like the one I've shown in
> "resultsmean" below?
>
> I've tried apply and lapply, still not got the correct arguments. As
> usual, TIA.
>
> Jim
>
>> results
> [[1]]
> name LOR23 BIA23 MSE23 H0R23
> 1 0.2111122 -1.012228 -0.095937 0.035650 1.00
> 2 0.2111122 -0.836300 0.079991 0.042322 0.75
> 3 0.2111122 -0.518631 0.397659 0.214593 0.50
>
>
> [[2]]
> name LOR23 BIA23 MSE23 H0R23
> 1 0.2211122 -0.724630 0.191660 0.051308 1
> 2 0.2211122 -0.781812 0.134478 0.033872 1
> 3 0.2211122 -0.522109 0.394181 0.164628 0.75
>
>
> would like
>
>> resultsmean
> [[1]]
> name LOR23 BIA23 MSE23 H0R23
> 1 0.2111122 -0.78333 0.12734 0.097160 0.75
>
> [[2]]
> name LOR23 BIA23 MSE23 H0R23
> 1 0.2211122 -0.67566 0.2400 0.08266 0.916
>
lapply(results, FUN=colMeans)
Berend
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