column selection in list
If the columns of all elements of the list are in the same order, then
you can collapse it first and then extract.
out <- do.call("rbind", SPECSHOR_tx_Asfc)
out[ , "Asfc.median"]
Regards, Adai
Ivan Calandra wrote:
Hi everybody! I have a (stupid) question but I cannot find a way to do it! I have a list like:
> SPECSHOR_tx_Asfc
$cotau
SPECSHOR Asfc.median
38 cotau 381.0247
39 cotau 154.6280
40 cotau 303.3219
41 cotau 351.2933
42 cotau 156.5327
$eqgre
SPECSHOR Asfc.median
145 eqgre 219.5389
146 eqgre 162.5926
147 eqgre 146.3726
148 eqgre 127.6413
149 eqgre 274.2888
$gicam
SPECSHOR Asfc.median
263 gicam 174.7445
264 gicam 83.4821
265 gicam 157.6005
266 gicam 153.7519
267 gicam 344.9775
I would just like to remove the column "SPECSHOR" (or extract the other
one) so that it looks like
$cotau
Asfc.median
38 381.0247
39 154.6280
40 303.3219
41 351.2933
42 156.5327
etc.
How should I do it? I know how to select each element like
SPECSHOR_tx_Asfc[[1]], but I don't know how to select a single column
within an element.
Could you please help me on that?
Thanks
Ivan
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