Integration in R

On 08-01-2013, at 22:00, Berend Hasselman <bhh at xs4all.nl> wrote:

?...
David implemented the condition by multiplying by x[1]<x[2] which  
in a numeric context is 0 when x[1]<x[2] en 1 when x[1]>=x[2].

OOPS!! Reverse the 0 and the 1 in that sentence (TRUE becomes 1 and  
FALSE becomes 0)

I didn't worry about which direction was used for the inequality in  
this case because of consideration of symmetry. (Thinking about it  
now, I still think I managed to choose the correct direction.)   
Obviously such a cavalier attitude should not be carried over to the  
general situation.

David Winsemius, MD
Alameda, CA, USA