regexpr with accents

Hello,

Works with me:

d1 <- data.frame(V1 = 1:3,
     V2 = c("some text = 9", "some t?xt = 9", "some other text = 9"))

regexpr("some text = 9", d1$V2)
[1]  1 -1 -1
attr(,"match.length")
[1] 13 -1 -1
regexpr("some t?xt = 9", d1$V2)
[1] -1  1 -1
attr(,"match.length")
[1] -1 13 -1
d1$V1[regexpr("some text = 9",d1$V2) > 0] <- 9
d1$V1[regexpr("some t?xt = 9",d1$V2) > 0] <- 9
d1
   V1                  V2
1  9       some text = 9
2  9       some t?xt = 9
3  3 some other text = 9

What do you mean by "it did not work"? What was the contents of 'd1'?

sessionInfo()
R version 2.15.1 (2012-06-22)
Platform: x86_64-pc-mingw32/x64 (64-bit)

locale:
[1] LC_COLLATE=Portuguese_Portugal.1252 LC_CTYPE=Portuguese_Portugal.1252
[3] LC_MONETARY=Portuguese_Portugal.1252 LC_NUMERIC=C
[5] LC_TIME=Portuguese_Portugal.1252

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods base

loaded via a namespace (and not attached):
[1] fortunes_1.5-0

Hope this helps,

Rui Barradas

Em 06-08-2012 06:55, Luca Meyer escreveu:

Hello,

I have build a syntax to find out if a given substring is included in a larger string that works like this:

d1$V1[regexpr("some text = 9",d1$V2)>0] <- 9

and this works all right till "some text" contains standard ASCII set. However, it does not work when accents are included as the following:

d1$V1[regexpr("some t?xt = 9",d1$V2)>0] <- 9

I have tried to substitute "?" with several wildcards but it did not work, can anyone suggest how to have the syntax parse the string ignoring the accent?

Thank you in advance,

Luca

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