Populating then sorting a matrix and/or data.frame
That was a typo. It should have read: results[results$one < 100,] It does still fail. There is ONE column that is text. So my guess is that R is seeing that and assuming that the entire data.frame should be factors. -N
On 11/10/10 11:16 PM, Michael Bedward wrote:
Hello Noah, If you set these names...
names(results)<- c("one", "two", "three")
this won't work...
results[results$c< 100,]
because you don't have a column called "c" (unless that's just a typo in your post).
I tried making it a data.frame with foo<- data.frame(results) But that converted all the numeric values to factors!!!
Not sure what's going on there. If 'results' is a numeric matrix you should get a data.frame with numeric cols since under the hood this is just calling the as.data.frame function. Michael On 11 November 2010 16:02, Noah Silverman<noah at smartmediacorp.com> wrote:
Hi,
I have a process in R that produces a lot of output. My plan was to build
up a matrix or data.frame "row by row", so that I'll have a nice object with
all the resulting data.
I started with:
results<- matrix(ncol=3)
names(results)<- c("one", "two", "three")
Then, when looping through the data:
results<- rbind(results, c(a,b,c))
This seems to work fine. BUT, my problem arises when I want to filter, sort,
etc.
I tried (thinking like a data.frame):
results[results$c< 100,]
But that fails.
I tried making it a data.frame with
foo<- data.frame(results)
But that converted all the numeric values to factors!!! Which causes a
whole mess of problems.
Any ideas??
-N
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