Sequence generation in a table
Hi r-help-bounces at r-project.org napsal dne 09.12.2010 12:41:47:
Dear Sir, Sorry to bother you again. Sir, the R code provided by you gives me
following output.
yy <- lapply(c(257, 520, 110), seq, to=0, by=-100) yy
[[1]] [1] 257 157 57 [[2]] [1] 520 420 320 220 120 20 [[3]] [1] 110 10 The biggest constraint for me is here as an example I have taken only
three
cases i.e. c(257, 520, 110), however in reality I will be dealing with
no of
cases and that number is unknown. But your code will certainly generate
me the
required numbers. In above case for doing further calculations, I can
define say
yy1 = as.numeric(yy[[1]]) yy2 = as.numeric(yy[2]]) yy3 = as.numeric(yy[[3]])
Why? Those values are already numeric. lapply(yy, is.numeric) [[1]] [1] TRUE [[2]] [1] TRUE [[3]] [1] TRUE and you can use the same construction to perform almost any operation on list. lapply(yy, max) lapply(yy, mean) lapply(yy, sd) lapply(yy, t.test) Regards Petr
But when the number of cases are unknown, perhaps this is not the
practical
way of me defining individually. So is there any way that I can have all
the
sequence numbers generated can be accommodated in a single dataframe. I sincerely apologize for disturbing you Sir and hope I am able to put up
my
problem in a proper manner. Regards Vincy Pyne --- On Thu, 12/9/10, Jan van der Laan <rhelp at eoos.dds.nl> wrote: From: Jan van der Laan <rhelp at eoos.dds.nl> Subject: Re: [R] Sequence generation in a table To: r-help at r-project.org, vincy_pyne at yahoo.ca Received: Thursday, December 9, 2010, 10:57 AM Vincy, I suppose the following does what you want. yy is now a list which
allows for
differing lengths of the vectors.
yy <- lapply(c(257, 520, 110), seq, to=0, by=-100) yy[[1]]
[1] 257 157 57
yy[[2]]
[1] 520 420 320 220 120 20 Regards, Jan On 9-12-2010 11:40, Vincy Pyne wrote:
c(257, 520, 110)
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