HI,
str1<-"x$Expensive"
regexpr("\\$",str1)[1]
#[1] 2
?str2<-"x$Exp$Expression"
unlist(gregexpr("\\$",str2))
#[1] 2 6
A.K.
----- Original Message -----
From: Data Analytics Corp. <walt at dataanalyticscorp.com>
To: "r-help at R-project.org" <r-help at r-project.org>
Cc:
Sent: Monday, January 7, 2013 4:22 PM
Subject: [R] pattern matching
Hi,
I have a simple question.? Suppose I have a string "x$Expensive". I want to find the position of the $ in this string; i.e., I want a function that returns 2.? I tried grep, regexpr, etc with no luck, unless I'm just using them incorrectly.? Any suggestions?
Thanks,
Walt
________________________
Walter R. Paczkowski, Ph.D.
Data Analytics Corp.
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________________________
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(F) 609-936-3733
walt at dataanalyticscorp.com
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