is.numeric()

vec <- c(TRUE, FALSE, NA, NA)
sapply(vec,FUN=is.numeric)

is.numeric(vec[2])

is.numeric(vec[3])

On Wed, 21 Aug 2002, Ole Christensen wrote:

###
output + comments :
###

vec <- c(1.4, NA, NA, NA)
sapply(vec,FUN=is.numeric)

[1] TRUE TRUE TRUE TRUE

is.numeric(vec[2])

[1] TRUE

is.na(vec[2])

[1] TRUE

is.numeric(NA)

[1] FALSE


I would have expected that is.numeric() on vec[2], vec[3] and vec[4]
would give three times FALSE.


My attempt to try to vectorize is.numeric() using sapply() might be
nonsense. Is it possible to vectorize is.numeric() ?

You can vectorize anything.  You appear to be getting confused by the fact
that there is more than one sort of NA.

In the first case vec is a numeric vector, so the NAs in it are numeric
NAs. That is, they represent some number but you don't know which one
because you didn't measure it. This is numeric.

In the second case vec is a logical vector, so the NAs are logical NAs:
the value is TRUE or FALSE but you don't know which one.  This is not
numeric

You can also have character NAs, representing a missing character string.
This isn't numeric either.

The `default' NA produced when you type `NA' is a logical NA and so isn't
numeric.

There's also NaN, which represents the value of an undefined mathematical
operation, eg 0/0.

We need different types of NA because all the elements in a vector must be
of the same type.

        -thomas