Message-ID: <476251AD.2020501@statistik.uni-dortmund.de>
Date: 2007-12-14T09:49:33Z
From: Uwe Ligges
Subject: can I solve this equation in R----29.040x+1=327.727x^(355.768x/(1-x))
In-Reply-To: <BAY141-DAV241281A93A369D45678CEF0670@phx.gbl>
Well, numerically by re-writing
-29.040x+1 = 327.727x^(355.768x/(1-x))
0 = 327.727x^(355.768x/(1-x)) - (-29.040x+1)
0^2 = (327.727x^(355.768x/(1-x)) - (-29.040x+1))^2
and then minimizing the right hand side:
optimize(function(x)
(327.727 * x^(355.768*x / (1-x)) - (-29.040*x + 1))^2,
interval = c(0, 1))
Uwe Ligges
Xin wrote:
> -29.040x+1=327.727x^(355.768x/(1-x))
> [[alternative HTML version deleted]]
>
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