question about deparse(substitute(...))
On Thu, Jan 13, 2011 at 7:36 PM, Sean Zhang <seanecon at gmail.com> wrote:
Dear R helpers:
I like to apply deparse(substitute()) on multiple arguments to collect the
names of the arguments into a character vector.
I used function test.fun as below. it works when there is only one input
argument. but it does not work for multiple arguements. can someone kindly
help?
test.fun <- function(...){deparse(substitute(...))}
test.fun(x) #this works
test.fun(x,y,z) # I like c('x','y','z') be the output, but cannot get it.
Try this:
test.fun.2 <- function(...) sapply(match.call()[-1], deparse) test.fun.2(x, y, z)
[1] "x" "y" "z" You could consider replacing sapply with lapply since it will return a list of vectors if the arguments are complex -- so that would consistently return a list.
Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com