Beginner Question: List value without Levels
Hi dabs, Thanks for that. Part of your problem is that the data in myVals is not being stored as numbers, it is stored as factors. If "," is your decimal separator, then something like: myVal2 <- unlist(myVal) myVal2 <- as.numeric(levels(myVal2))[myVal2] should convert it to numeric class data, at which point, all you need to do is: myVal2 * data and because R is vectorized, each element of "myVal2" will be multiplied by each element of "data". If "," is not a decimal separator and indicates coordinates or something, then you will need to handle it a little differently. Cheers, Josh
On Tue, May 24, 2011 at 12:31 PM, dabs <ragon016 at web.de> wrote:
Hey Joshua, thanks for your help. Here are the dput outputs :)!
dput(myVal)
structure(list(I = structure(1L, .Label = "4,5", class = "factor"),
? ?V = structure(1L, .Label = "4,2", class = "factor"), L = structure(1L,
.Label = "3,8", class = "factor"),
? ?F = structure(1L, .Label = "2,8", class = "factor"), C = structure(1L,
.Label = "2,5", class = "factor"),
? ?M = structure(1L, .Label = "1,9", class = "factor"), A = structure(1L,
.Label = "1,8", class = "factor"),
? ?G = structure(1L, .Label = "-0,4", class = "factor"), T = structure(1L,
.Label = "-0,7", class = "factor"),
? ?W = structure(1L, .Label = "-0,9", class = "factor"), S = structure(1L,
.Label = "-0,8", class = "factor"),
? ?Y = structure(1L, .Label = "-1,3", class = "factor"), P = structure(1L,
.Label = "-1,6", class = "factor"),
? ?H = structure(1L, .Label = "-3,2", class = "factor"), Q = structure(1L,
.Label = "-3,5", class = "factor"),
? ?D = structure(1L, .Label = "-3,5", class = "factor"), N = structure(1L,
.Label = "-3,5", class = "factor"),
? ?E = structure(1L, .Label = "-3,5", class = "factor"), K = structure(1L,
.Label = "-3,9", class = "factor"),
? ?R = structure(1L, .Label = "-4,5", class = "factor")), .Names = c("I",
"V", "L", "F", "C", "M", "A", "G", "T", "W", "S", "Y", "P", "H",
"Q", "D", "N", "E", "K", "R"), class = "data.frame", row.names = c(NA,
-1L))
And
dput(data)
structure(c(28L, 8L, 11L, 14L, 17L, 34L, 7L, 26L, 15L, 26L, 10L,
9L, 12L, 8L, 11L, 21L, 19L, 33L, 7L, 7L), .Dim = 20L, .Dimnames =
structure(list(
? ?data= c("A", "C", "D", "E", "F", "G", "H", "I", "K",
? ?"L", "M", "N", "P", "Q", "R", "S", "T", "V", "W", "Y")), .Names =
"data"), class = "table")
Cheers!
dabs
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Joshua Wiley Ph.D. Student, Health Psychology University of California, Los Angeles http://www.joshuawiley.com/