Replace element with pattern
try this:
x <- rbind("Peak Usage : init:2359296, used:15859328, committed:15892480,max:50331648Current Usage : init:2359296, used:15857920,committed:15892480, max:50331648|-------------------|")
apply(x, 1, function(a) sub("(Current.*?[/|]).*", "\\1", a))
[1] "Peak Usage : init:2359296, used:15859328, committed:15892480,max:50331648Current Usage : init:2359296, used:15857920,committed:15892480, max:50331648|"
Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it.
On Fri, Nov 1, 2013 at 4:09 AM, <mohan.radhakrishnan at polarisft.com> wrote:
Hi,
I have a data frame with one column and several rows of the form.
"Peak Usage : init:2359296, used:15859328, committed:15892480,
max:50331648Current Usage : init:2359296, used:15857920,
committed:15892480, max:50331648|-------------------|"
I tested the regex
Current.*?[\|]
in an online tester which greedily matches upto the first 'pipe' character
Current Usage : init:2359296, used:15857920, committed:15892480,
max:50331648|
This is what I want.
I tried to replace the entire rows using
apply( y, 1, function(x) gsub(x,"Current.*?[/|]",x)) which didn't work.
How is this done ? I also want to recursively apply some more patterns one
by one on the rows till I reduce it to exactly what I want. Is there a way
to do this without loops ?
Thanks,
Mohan
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