Message-ID: <1361212232.40867.YahooMailNeo@web142605.mail.bf1.yahoo.com>
Date: 2013-02-18T18:30:32Z
From: arun
Subject: reading data
In-Reply-To: <CAHc7oGErcM9QYcB8NA-bmA=ioH0mU6PuRwXrQsFiACn035etyA@mail.gmail.com>
Hi Vera,
Not sure I understand your question.
Your statement
"In my lista?I?can?t merge rows to have the group, because the idea is
for each file count? frequencies of mm, when b<0.01. after that I
want a graph like the graph in attach."
?files<-paste("MSMS_",23,"PepInfo.txt",sep="")
read.data<-function(x) {names(x)<-gsub("^(.*)\\/.*","\\1",x); lapply(x,function(y) read.table(y,header=TRUE,sep = "\t",stringsAsFactors=FALSE,fill=TRUE))}
lista<-do.call("c",lapply(list.files(recursive=T)[grep(files,list.files(recursive=T))],read.data))
names(lista)<-paste("group_",gsub("\\d+","",names(lista)),sep="")
res2<-split(lista,names(lista))
res3<- lapply(res2,function(x) {names(x)<-paste(gsub(".*_","",names(x)),1:length(x),sep="");x})
res4<-lapply(seq_along(res3),function(i) do.call(rbind,lapply(res3[[i]], function(x) x[x[["b"]]<0.01,])))
names(res4)<- names(res2)
res4
lapply(res4,function(x) table(x$mm))
#$group_a
#2 3
#9 3
#$group_b
#2 3
#6 2
#$group_c
#2 3
#3 1
If you want the separate counts per a1,a2,a3 within the group:
res4<-lapply(seq_along(res3),function(i) do.call(rbind,lapply(res3[[i]], function(x) table(x$mm[x[["b"]]<0.01]))))
?names(res4)<- names(res2)
?res4
#$group_a
?#? 2 3
#a1 3 1
#a2 3 1
#a3 3 1
#$group_b
?#? 2 3
#b1 3 1
#b2 3 1
#$group_c
?#? 2 3
#c1 3 1
I haven't gone through the rest of the codes as I was not sure about what you want.
A.K.
________________________________
From: Vera Costa <veracosta.rt at gmail.com>
To: arun <smartpink111 at yahoo.com>
Sent: Monday, February 18, 2013 10:27 AM
Subject: Re: reading data
Hi!!!
I'm coming to ask a new question.
I want a function to do my statistics. I start with you had send me:
z.plot <- function(directory,number) {
??setwd(directory)
?indx<-gsub("[./]","",list.dirs())
?indx1<- indx[indx!=""]
?print(indx1)
?files<-paste("MSMS_",number,"PepInfo.txt",sep="")
?read.data<-function(x) {names(x)<-gsub("^(.*)\\/.*","\\1",x); lapply(x,function(y) read.table(y,header=TRUE,sep = "\t",stringsAsFactors=FALSE,fill=TRUE))}
?lista<-do.call("c",lapply(list.files(recursive=T)[grep(files,list.files(recursive=T))],read.data))
?print(lista)
?#names(lista)<-paste("group_",gsub("\\d+","",names(lista)),sep="")?ve = TRUE)
?}
z.plot("C:/Users/Vera Costa/Desktop/dados.lixo",23)
In my lista?I?can?t merge rows to have the group, because the idea is for each file count? frequencies of mm, when b<0.01. after that I want a graph like the graph in attach.
When I had 2 groups and knew the name of the groups, I did the code (but Know I have more groups and, maybe, I don?t know the name of the groups):
z.plot <- function(directory,number) {
?#reading data
??setwd(directory)
?direct<-dir(directory,pattern = paste("MSMS_",number,"PepInfo.txt",sep=""), full.names = FALSE, recursive = TRUE)
?directT <- direct[grepl("^t", direct)]
?directC <- direct[grepl("^c", direct)]
?lista<-lapply(direct, function(x) read.table(x,header=TRUE, sep = "\t"))
?listaC<-lapply(directC, function(x) read.table(x,header=TRUE, sep = "\t"))
?listaT<-lapply(directT, function(x) read.table(x,header=TRUE, sep = "\t"))
?#count different z values
?cab <- vector()
??? for (i in 1:length(lista)) {
???????? dc<-lista[[i]][ifelse(lista[[i]]$FDR<0.01, TRUE, FALSE),]
??????? dc<-table(dc$z)
??????? cab <- c(cab, names(dc))
??}
?#Relative freqs to construct the graph
??? cab <- unique(cab)
??? d <- matrix(ncol=length(cab))
?dci<- d[-1,]
??? dcf <- d[-1,]
?dti <- d[-1,]
?dtf <- d[-1,]
??? for (i in 1:length(listaC)) {
??#Relative freq of all data
??dcc<-listaC[[i]]
??dcc<-table(factor(dcc$z, levels=cab))
??dci<- rbind(dci, dcc)
??rownames(dci)<-rownames(1:(nrow(dci)), do.NULL = FALSE, prefix = "c")
??#Relative freq of data with FDR<0.01
??dcc1<-listaC[[i]][ifelse(listaC[[i]]$FDR<0.01, TRUE, FALSE),]
??dcc1<-table(factor(dcc1$z, levels=cab))
??dcf<- rbind(dcf,dcc1)
??rownames(dcf)<-rownames(1:(nrow(dcf)), do.NULL = FALSE, prefix = "c")
??????? }
?for (i in 1:length(listaT)) {
??#Relative freq of all data
??dct<-listaT[[i]]
??dct<-table(factor(dct$z, levels=cab))
??dti<- rbind(dti, dct)
??rownames(dti)<-rownames(1:(nrow(dti)), do.NULL = FALSE, prefix = "t")
??#Relative freq of data with FDR<0.01
??dct1<-listaT[[i]][ifelse(listaT[[i]]$FDR<0.01, TRUE, FALSE),]
??dct1<-table(factor(dct1$z, levels=cab))
??dtf<- rbind(dtf,dct1)
??rownames(dtf)<-rownames(1:(nrow(dtf)), do.NULL = FALSE, prefix = "t")
??????? }
??freq.i<-rbind(dci,dti)
??freq.f<-rbind(dcf,dtf)
??freq.rel.i<-freq.i/apply(freq.i,1,sum)
??freq.rel.f<-freq.f/apply(freq.f,1,sum)?
#Graph plot
colour<-sample(rainbow(nrow(freq.rel.i)))
par(mfrow=c(1,2))
barplot(freq.rel.i,beside=T,main=("Sample"),xlab="Charge",ylab="Relative Frequencies",col=colour,legend.text = rownames(freq.rel.i))
barplot(freq.rel.f,beside=T,main=("Sample with FDR<0.01"),xlab="Charge",ylab="Relative Frequencies",col=colour,legend.text = rownames(freq.rel.f))
#average of the group (except c1&t1)
freqs<-rbind(dcf[-1,], dtf[-1,])
average<-apply(freqs,2,mean)
#chisquare test function
chisq.test<-function(x,y){
?somax<-sum(x)
?somay<-sum(y)
?nj.<-x+y
?nj<-sum(nj.)
?ejx<-(nj./nj)*somax
?ejy<-(nj./nj)*somay
?ETx<-((x-ejx)^2)/ejx
?ETy<-((y-ejy)^2)/ejy
?ETobs<-sum(ETx)+sum(ETy)
?pvalue<-1-pchisq(c(ETobs),df=length(x|y)-1,lower.tail=TRUE)
?return(pvalue)
?}
#pvalues of the chisquare test between sample and average (H0: two samples has the same distribution)
pvalues<-c()
for (i in 1:(nrow(freqs))){
a<-chisq.test(freqs[i,],average)
pvalues<-c(pvalues,a)
}
#data frame with final p-values
dataframe<-data.frame(c(rownames(freqs)), c(pvalues))
colnames(dataframe)<-c("sample name","pvalue")
print(dataframe)
}
z.plot("C:/Users/Vera/Desktop/data",23)
Thank you again
2013/2/17 arun <smartpink111 at yahoo.com>
HI Vera,
>
>No problem.? I am cc:ing to r-help.
>
>A.K.
>
>
>
>
>
>
>________________________________
>From: Vera Costa <veracosta.rt at gmail.com>
>To: arun <smartpink111 at yahoo.com>
>Sent: Sunday, February 17, 2013 5:44 AM
>Subject: Re: reading data
>
>
>
>Hi. Thank you. It works now:-)
>And yes, I use windows.
>Thank you very much.
>No dia 17 de Fev de 2013 00:44, "arun" <smartpink111 at yahoo.com> escreveu:
>
>Hi Vera,
>>
>>Have you tried the suggestion?
>>
>>Are you using Windows?
>>Thanks,
>>Arun
>>
>>
>>
>>
>>
>>
>>________________________________
>>From: Vera Costa <veracosta.rt at gmail.com>
>>To: arun <smartpink111 at yahoo.com>
>>Sent: Saturday, February 16, 2013 7:10 PM
>>Subject: Re: reading data
>>
>>
>>Thank you.
>>In mine, I have an error " 'what' must be a character string or a function".
>>I need to do equivalent in my system.
>>Thank you and sorry one more time.
>>No dia 16 de Fev de 2013 23:53, "arun" <smartpink111 at yahoo.com> escreveu:
>>
>>Hi,
>>>You didn't mention what the error message or whether you are reading file names which are? not "mmmmm11kk.txt".
>>>
>>>It is workiing on my system as I run it again.
>>>?c() combine values into a vector or list.
>>>
>>>?sessionInfo()
>>>R version 2.15.1 (2012-06-22)
>>>Platform: x86_64-pc-linux-gnu (64-bit)
>>>
>>>locale:
>>>?[1] LC_CTYPE=en_CA.UTF-8?????? LC_NUMERIC=C?????????????
>>>?[3] LC_TIME=en_CA.UTF-8??????? LC_COLLATE=en_CA.UTF-8???
>>>?[5] LC_MONETARY=en_CA.UTF-8??? LC_MESSAGES=en_CA.UTF-8??
>>>?[7] LC_PAPER=C???????????????? LC_NAME=C????????????????
>>>?[9] LC_ADDRESS=C?????????????? LC_TELEPHONE=C???????????
>>>[11] LC_MEASUREMENT=en_CA.UTF-8 LC_IDENTIFICATION=C??????
>>>
>>>attached base packages:
>>>[1] stats???? graphics? grDevices utils???? datasets? methods?? base????
>>>
>>>other attached packages:
>>>[1] stringr_0.6.2? reshape2_1.2.2
>>>
>>>loaded via a namespace (and not attached):
>>>[1] plyr_1.8
>>>
>>>
>>>#code
>>>
>>>
>>>res<-do.call(c,lapply(list.files(recursive=T)[grep("mmmmm11kk",list.files(recursive=T))],function(x) {names(x)<-gsub("^(.*)\\/.*","\\1",x); lapply(x,function(y) read.table(y,header=TRUE,stringsAsFactors=FALSE,fill=TRUE))}))? #it seems like one of the rows of your file doesn't have 6 elements, so added fill=TRUE
>>>?names(res)<-paste("group_",gsub("\\d+","",names(res)),sep="")
>>>res2<-split(res,names(res))
>>>res3<- lapply(res2,function(x) {names(x)<-paste(gsub(".*_","",names(x)),1:length(x),sep="");x})
>>>#result
>>>
>>>res3
>>>#$group_a
>>>#$group_a$a1
>>>???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>
>>>$group_a$a2
>>>???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>
>>>$group_a$a3
>>>???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>
>>>
>>>$group_b
>>>$group_b$b1
>>>???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>
>>>$group_b$b2
>>>???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>
>>>
>>>$group_c
>>>$group_c$c1
>>>???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>
>>>
>>>A.K.
>>>
>>>
>>>
>>>________________________________
>>>From: Vera Costa <veracosta.rt at gmail.com>
>>>To: arun <smartpink111 at yahoo.com>
>>>Sent: Saturday, February 16, 2013 6:32 PM
>>>Subject: Re: reading data
>>>
>>>
>>>Sorry again... In:
>>>res<-do.call(c,lapply(list.files(recursive=T)[grep("...
>>>What is this c? In do.call(c,?? When I put this row im R, I have an error.
>>>Thank you
>>>No dia 15 de Fev de 2013 18:11, "arun" <smartpink111 at yahoo.com> escreveu:
>>>
>>>Hi,
>>>>No problem.
>>>>
>>>>BTW, these questions are not stupid..
>>>>Arun
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>________________________________
>>>>From: Vera Costa <veracosta.rt at gmail.com>
>>>>To: arun <smartpink111 at yahoo.com>
>>>>Sent: Friday, February 15, 2013 1:08 PM
>>>>Subject: Re: reading data
>>>>
>>>>
>>>>Thank you very much.
>>>>
>>>>I will try to apply and after I tell you if it is ok :-)
>>>>
>>>>Thank you and sorry about this questions (sometimes stupid questions).
>>>>
>>>>
>>>>
>>>>
>>>>2013/2/15 arun <smartpink111 at yahoo.com>
>>>>
>>>>HI,
>>>>>No problem.
>>>>>?c() for concatenate to vector or list().
>>>>>If I use do.call(cbind,..) or do.call(rbind,...)
>>>>>
>>>>>do.call(cbind,lapply(list.files(recursive=T)[grep("mmmmm11kk",list.files(recursive=T))],function(x) {names(x)<-gsub("^(.*)\\/.*","\\1",x); lapply(x,function(y) read.table(y,header=TRUE,stringsAsFactors=FALSE,fill=TRUE))}))?
>>>>>#?? [,1]??? [,2]??? [,3]??? [,4]??? [,5]??? [,6]??
>>>>>#a1 List,11 List,11 List,11 List,11 List,11 List,11
>>>>>
>>>>>
>>>>>?do.call(rbind,lapply(list.files(recursive=T)[grep("mmmmm11kk",list.files(recursive=T))],function(x) {names(x)<-gsub("^(.*)\\/.*","\\1",x); lapply(x,function(y) read.table(y,header=TRUE,stringsAsFactors=FALSE,fill=TRUE))}))?
>>>>>#???? a1????
>>>>>#[1,] List,11
>>>>>#[2,] List,11
>>>>>#[3,] List,11
>>>>>#[4,] List,11
>>>>>#[5,] List,11
>>>>>#[6,] List,11
>>>>>ie.
>>>>>list within in a list
>>>>>
>>>>>?restrial<-lapply(list.files(recursive=T)[grep("mmmmm11kk",list.files(recursive=T))],function(x) {names(x)<-gsub("^(.*)\\/.*","\\1",x); lapply(x,function(y) read.table(y,header=TRUE,stringsAsFactors=FALSE,fill=TRUE))})
>>>>>?str(restrial)
>>>>>#List of 6
>>>>># $ :List of 1
>>>>>? #..$ a1:'data.frame':??? 6 obs. of? 11 variables:
>>>>>? .#. ..$ Id: chr [1:6] "aAA" "aAAAA" "aA" "aAA" ...
>>>>>? #.. ..$ M : chr [1:6] "1" "1" "2" "1" ...
>>>>>? #. ..$ mm: int [1:6] 2 2 1 2 3 2
>>>>>? #. ..$ x : int [1:6] 739 2263 1 1965 3660 1972
>>>>>? -----------------------------------------------------------------
>>>>>str(res)
>>>>>#List of 6
>>>>># $ a1:'data.frame':??? 6 obs. of? 11 variables:
>>>>>?# ..$ Id: chr [1:6] "aAA" "aAAAA" "aA" "aAA" ...
>>>>>? #..$ M : chr [1:6] "1" "1" "2" "1" ...
>>>>>?# ..$ mm: int [1:6] 2 2 1 2 3 2
>>>>>?# ..$ x : int [1:6] 739 2263 1 1965 3660 1972
>>>>>-----------------------------------------------------------------
>>>>>
>>>>>You mentioned about naming this to "group_a","group_b". etc..
>>>>>
>>>>>?names(res)<-paste("group_",gsub("\\d+","",names(res)),sep="")
>>>>>res2<-split(res,names(res))
>>>>>
>>>>>res3<- lapply(res2,function(x) {names(x)<-paste(gsub(".*_","",names(x)),1:length(x),sep="");x})
>>>>>?res3$group_a
>>>>>$a1
>>>>>
>>>>>#???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>>>#1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>#2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>#3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>#4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>#5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>#6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>
>>>>>#$a2
>>>>>
>>>>>#???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>>>#1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>#2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>#3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>#4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>#5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>#6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>
>>>>>#$a3
>>>>>
>>>>>?# ?? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>>>#1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>#2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>#3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>#4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>#5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>#6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>A.K.
>>>>>
>>>>>________________________________
>>>>>From: Vera Costa <veracosta.rt at gmail.com>
>>>>>To: arun <smartpink111 at yahoo.com>
>>>>>Sent: Friday, February 15, 2013 12:39 PM
>>>>>Subject: Re: reading data
>>>>>
>>>>>
>>>>>
>>>>>Thank you very much and sorry my questions.
>>>>>
>>>>>But this code isn't grouping for letters sure? I mean, a1,a2,a3 is the same group, (the first letter give me the name of the group)
>>>>>
>>>>>Another question, in do.call, you did do.call (c,.....) .What is c?
>>>>>
>>>>>Sorry
>>>>>
>>>>>
>>>>>
>>>>>2013/2/15 arun <smartpink111 at yahoo.com>
>>>>>
>>>>>HI,
>>>>>>
>>>>>>Just to add:
>>>>>>
>>>>>>
>>>>>>res<-do.call(c,lapply(list.files(recursive=T)[grep("mmmmm11kk",list.files(recursive=T))],function(x) {names(x)<-gsub("^(.*)\\/.*","\\1",x); lapply(x,function(y) read.table(y,header=TRUE,stringsAsFactors=FALSE,fill=TRUE))}))? #it seems like one of the rows of your file doesn't have 6 elements, so added fill=TRUE
>>>>>>
>>>>>>?names(res)<-paste("group_",gsub("\\d+","",names(res)),sep="")
>>>>>>res[grep("group_b",names(res))]
>>>>>>
>>>>>>I am not sure how you want the grouped data to look like.? If you want something like this:
>>>>>>res1<-do.call(rbind,res)
>>>>>>res2<-lapply(split(res1,gsub("[.0-9]","",row.names(res1))),function(x) {row.names(x)<-1:nrow(x);x})
>>>>>>res2
>>>>>>#$group_a
>>>>>>
>>>>>>?# ??? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>>>>#1??? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>>#2? aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>>#3???? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>>#4??? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>>#5?? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>>#6???? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>>#7??? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>>#8? aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>>#9???? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>>#10?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>>#11? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>>#12??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>>#13?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>>#14 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>>#15??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>>#16?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>>#17? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>>#18??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>>
>>>>>>
>>>>>>#$group_b
>>>>>>?# ??? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>>>>#1??? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>>#2? aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>>#3???? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>>#4??? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>>#5?? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>>#6???? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>>#7??? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>>#8? aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>>#9???? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>>#10?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>>#11? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>>#12??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>>
>>>>>>#$group_c
>>>>>>
>>>>>>?# ?? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>>>>#1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>>#2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>>#3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>>#4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>>#5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>>#6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>>
>>>>>>
>>>>>>#or if you want it like this:
>>>>>>res2<-split(res,names(res))
>>>>>>
>>>>>>res2[["group_b"]]
>>>>>>
>>>>>>#$group_b
>>>>>>#???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>>>>#1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>>#2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>>#3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>>#4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>>#5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>>#6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>>
>>>>>>#$group_b
>>>>>>?# ?? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
>>>>>>#1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
>>>>>>#2 aAAAA? 1? 2 2263 0.0004000? 2? 2 AR??? 4???? 7640 8926
>>>>>>#3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
>>>>>>#4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
>>>>>>#5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
>>>>>>#6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
>>>>>>
>>>>>>Hope this helps.
>>>>>>
>>>>>>A.K.
>>>>>>
>>>>>>
>>>>>>
>>>>>>----- Original Message -----
>>>>>>From: "veracosta.rt at gmail.com" <veracosta.rt at gmail.com>
>>>>>>To: smartpink111 at yahoo.com
>>>>>>Cc:
>>>>>>Sent: Friday, February 15, 2013 9:15 AM
>>>>>>Subject: reading data
>>>>>>
>>>>>>Hi,
>>>>>>I post yesterday and you helped me. I have little problem.
>>>>>>
>>>>>>At first, I never worked with regular expressions...
>>>>>>
>>>>>>The code that you gave me it's ok, but my files are inside the folders a1,a2,a3. I try to explain better.
>>>>>>
>>>>>>I have one folder named "data". Inside this folder I have some other folders named "a1","a2","b1",b2",...and inside of each one of that I have some files. I want only the file "mmmmmm.txt" (in all folders I have One file with this name).
>>>>>>The name of the folder give me the name of the group,but I need to read the file inside. And after, have "group_a", group_"b"...because I need to work with this data grouped (and know the name of the group).
>>>>>>
>>>>>>Thank you.
>>>>>>???
>>>>>???
>>>>
>>>
>>
>????????????????????????????????