Message-ID: <t10aq09891sola387glkops8sfv1dfduuq@4ax.com>
Date: 2004-11-24T21:42:46Z
From: Duncan Murdoch
Subject: Searching for antilog function
In-Reply-To: <41A4E32B.30300@pdq.com>
On Wed, 24 Nov 2004 14:38:19 -0500, "Heather J. Branton" <hjb at pdq.com>
wrote :
>Thank you so much for each of your responses. But to make sure I am
>clear (in my own mind), is this correct?
>
>If x = 2^y
>Then y = log2(x)
Yes, that's right.
Duncan Murdoch