How to write string dynamicly?
Try this:
idx <- match("Species", names(iris))
lda(iris[-idx], iris[,idx])
On 12/29/06, Feng Qiu <hustqiufeng at sohu.com> wrote:
Hi Gabor:
Thank you! But it didn't work.
Since lda() takes the variable
name as the input parameter.
That is not correct. It takes the variable itself, not its name, as input.
So what I was trying to do is "make the name dynamically". I used sprintf() to generate a variable name, such as "V16". But it seems that the function doesn't recognize the generated name. For example, lda(V16,data=mydata) works, But,
That is not a valid argument sequence. See ?lda
lda(sprintf("V%d",k),data=mydata) does not work, where k=16. So I guess the
name generated by sprintf is not the parameter wanted. But I have no idea
about it.
Best,
Feng
----- Original Message -----
From: "Gabor Grothendieck" <ggrothendieck at gmail.com>
To: "Feng Qiu" <fqiu at gatech.edu>
Cc: <r-help at stat.math.ethz.ch>
Sent: Wednesday, December 27, 2006 1:56 PM
Subject: Re: [R] How to write string dynamicly?
Try: lda(iris[-5], iris[,5]) On 12/26/06, Feng Qiu <fqiu at gatech.edu> wrote:
Hi everyone:
I'm trying to compose a string dynamicly for the parameter input
of
some function. For example:
In package MASS, function lda() require to input the name of predictor
variable. Let's say the 16th column is the predictor variable. Then we
call
the function like this: lda(V16~., data=mydata). I don't want to
hard-code
the call, instead, I would like to use a dynamic expression for this
parameter so that I can use my program on different set of data.
I guess there,- are some function that can do this, but I didn't
find
it in "Introduction to R" so far, could someone please tell me this kind
of
function? Thank you!
Best,
Feng
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