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quotation marks and scan

(1) The backslashes are not really there; they are an artefact of the R 
print() function.
Try cat(u,"\n").  I think this might be an FAQ.

(2) Is not your problem the fact that your are setting "replacement" 
equal to the
thing you are trying to get rid of?  I.e. don't you want

     v <- gsub(pattern='\"',replacement='',x=u)     ???

Either I am misunderstanding your intent or you need another cup of coffee.

     cheers,

     Rolf
On 11/18/13 11:07, Erin Hodgess wrote: