Message-ID: <788330.27674.qm@web32808.mail.mud.yahoo.com>
Date: 2008-03-13T18:53:18Z
From: John Kane
Subject: Splitting a set of vectors in a list (Solved )
In-Reply-To: <da79af330803131129l3feff84r47f69f0101ec085c@mail.gmail.com>
My thanks to Henrique Dallazuanna and Phil Spector.
Both solutions worked well.
Phil suggested that an alterative to my function would
be
vect1 = sapply(mylist,'[[',1)
and I see that Henrique used `[` in his solution.
Can you point me to some documentation that discusses
these usages. I have seen them before but I have never
actually figured out how to use them.?
Thanks.
Problem and solutions
========================================================
mylist <- list(aa=c("cat","peach" ), bb=c("dog",
"apple", "iron"),
cc = c("rabbit", "orange", "zinc", "silk"))
myfun <- function(dff) dff[1]
vect1 <- unlist(lapply(mylist, myfun))
# Desired output
t(cbind( c("cat" , "peach" , NA, NA), bbb <- c("dog"
, "apple" ,"iron", NA),
ccb <- c("rabbit" ,"orange" ,"zinc" , "silk" )))
# Phil Spector's approach
mlen = max(sapply(mylist,length))
eqlens = lapply(mylist,function(x)if(length(x) < mlen)
c(x,rep('',mlen-length(x))) else x)
do.call(rbind,eqlens)
# "Henrique Dallazuanna" <wwwhsd at gmail.com>
# I added the t()
t(as.data.frame(lapply(mylist, `[`,
1:max(unlist(lapply(mylist,
length))))))
[[elided trailing spam]]