weighting means
Hi everyone, I've got a dataframe called 'faculty'. I want to do a weighted mean on the column called 'Q8' weighted by the contents of column 'CETP'. In addition, I need to operate on the result of splitting 'faculty' according to the contents of a column 'FACULTY'. For example
lapply(split(faculty$Q8, faculty$FACULTY), mean)
$"1" [1] 2.2 $"2" [1] 1.888889 gives the mean of 'Q8' after splitting by 'FACULTY'. When I try this with weighted.mean, it doesn't work because I don't know how to specify the result of the split as the argument for weighted.mean. For example,
lapply(split(faculty$Q8, faculty$FACULTY), weighted.mean)
$"1" [1] 2.2 $"2" [1] 1.888889 gives the same results as above because I haven't specified the vector to use for weighting. The following doesn't work at all for the obvious reason that weighted.mean is not operating on the result of the split.
lapply(split(faculty$Q8, faculty$FACULTY), weighted.mean(faculty$Q8,
faculty$CETP)) Error in match.fun(FUN) : not function, character, or symbol: "weighted.mean(faculty$Q8, faculty$CETP)"
Any ideas? -Tim
Tim Wilson | Visit Sibley online: | Check out: Henry Sibley HS | http://www.isd197.org | http://www.zope.com W. St. Paul, MN | | http://slashdot.org wilson at visi.com | <dtml-var pithy_quote> | http://linux.com -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._