NA and NaN question
Thanks, now I understand what's happening. Maybe a line explaining this could be added to the help text for mean? Pascal Niklaus
On Wed 07-Jan-2009 13:29:25 Prof Brian Ripley wrote:
Pascal A. Niklaus wrote:
Hi all, I ran into a problem in some of my code that could be traced back to 'mean' sometimes returning NA and sometimes NaN, depending on the value of na.rm:
mean(c())
[1] NA
mean(c(NA),na.rm=T)
[1] NaN However, I don't understand the reasoning behind this and would appreciate and explanation. I understand that the mean of an empty vector is not definied,
Not so, it is well-defined as 0/0 = NaN.
but I don't understand why it matters whether the vector was empty from the beginning
You didn't try that case: mean(numeric(0)) is also NaN. The issue is that
> typeof(c())
[1] "NULL" is not numeric (not evan a vector), and so mean() of it is undefined.
> or only after removing the NAs.
Speculation (and wrong).
Pascal Niklaus
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