binary order combinations
Sorry,
I misread it first. I tried:
library(quantreg)
test.combos<-lapply(1:15,function(x)
{combos(15,x)
})
It gives me a list with an order that is somewhat different from
before, but I am not sure it helps me much:
[[1]]
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14]
[1,] 1 2 3 4 5 6 7 8 9 10 11 12 13 14
[,15]
[1,] 15
[[2]]
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14]
[1,] 1 1 1 1 1 1 1 1 1 1 1 1 1 1
[2,] 2 15 14 13 12 11 10 9 8 7 6 5 4 3
[,15] [,16] [,17] [,18] [,19] [,20] [,21] [,22] [,23] [,24] [,25] [,26]
[1,] 2 2 2 2 2 2 2 2 2 2 2 2
[2,] 3 15 14 13 12 11 10 9 8 7 6 5
Dimitri
On 9/5/08, roger koenker <rkoenker at uiuc.edu> wrote:
You need to read the help file ?combos, and then use it to do indexing of your objects, it only knows how to construct the integer combinations given a pair (n,p). url: www.econ.uiuc.edu/~roger Roger Koenker email rkoenker at uiuc.edu Department of Economics vox: 217-333-4558 University of Illinois fax: 217-244-6678 Champaign, IL 61820 On Sep 5, 2008, at 10:23 AM, Dimitri Liakhovitski wrote:
I am not sure it can do it. Besides, I ran a test of combos from quantreg:
library(quantreg)
H<-1:3
test.combos<-lapply(1:3,function(x)
{combn(H,x)
})
Every time I tried it crashed my R...
:(
Dimitri
On 9/5/08, roger koenker <rkoenker at uiuc.edu> wrote:
Does ?combos in the quantreg package do what you want? url: www.econ.uiuc.edu/~roger Roger Koenker email rkoenker at uiuc.edu Department of Economics vox: 217-333-4558 University of Illinois fax: 217-244-6678 Champaign, IL 61820 On Sep 5, 2008, at 9:58 AM, Dimitri Liakhovitski wrote:
Dear all!
I have a vector of names
names<-("V1", "V2", "V3",....., "V15")
I could create all possible combinations of these names (of all
lengths) using R:
combos<-lapply(1:15,function(x)
{combn(names,x)
})
I get a list with all possible combinations of elements of 'names'
that looks like this (just the very beginning of it):
[[1]] - the first element contains all combinations of 1 name
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13]
[,14]
[1,] "V1" "V2" "V3" "V4" "V5" "V6" "V7" "V8" "V9" "V10" "V11" "V12"
"V13"
"V14"
[,15] [1,] "V15" [[2]] - the second element contains all possible combinations of 2
names
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [1,] "V1" "V1" "V1" "V1" "V1" "V1" "V1" "V1" "V1" "V1" "V1" "V1"
"V1"
[2,] "V2" "V3" "V4" "V5" "V6" "V7" "V8" "V9" "V10" "V11" "V12" "V13"
"V14"
. . . etc. My question is: Is there any way to re-arrange all sub-elements of the above list (i.e., all possible combinations of names such as V1, V1:V3, V1:V2:V4:V5) in a binary system order. More specifically, according to this system: V1=1 V2=2 V3=4 V4=8 V5=16, etc.... So, I'd like those combinations to be arranged in a vector in the following order: 1. V1 (because V1=1) 2. V2 (because V2=2) 3. V1:V2 (because V1=1 and V2=2 so that 1+2=3) 4. V3 (because V3=4) 5. V1:V3 (because V1=1 and V3=4 so that 1+4=5) 6. V2:V3 (because V2=2 and V3=4 so that 2+4=6) 7. V1:V2:V3 (because V1=1 and V2=2 and V3=4 so that 1+2+4=7) 8. V4 (because V4=8) etc. Is it at all possible? Or maybe there is a way to create the name combinations in such an order in the first place? Thank you very much! Dimitri Liakhovitski
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______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.