a < b < c is alway TRUE
3 < 2
[1] FALSE
F < 1
[1] TRUE
as.numeric(F)
[1] 0 p.
On Fri, Jul 06, 2001 at 12:08:51PM +0200, Monika Ferster wrote:
Uwe Ligges writes:
> One of our students did something like: > > x[a < b < c] > > instead of > > x[a < b & b < c] > > > But why is > > 3 < 2 < 1 # [1] TRUE ??? >
3 < 2 < 1 seems to be seen like a double no because 3 < 2 < 1 < 0 returns F. It looks like the multiplication of -1 what is strange, because F corresponds to the value 0. So if you do (3<2)*(2<1) you get 0 and not the value of T (=1). -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
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