Gesendet: Donnerstag, 25. Juli 2013 um 20:53 Uhr
Von: "Rui Barradas" <ruipbarradas at sapo.pt>
An: dennis1991 at gmx.net
Cc: r-help at r-project.org
Betreff: Re: Aw: Re: Re: Re: [R] How to split two levels several times?
Hello,
I think the following does what you want. (I don't know if it makes much
sense but it works.)
lens <- rle(as.character(XXX$electrode))$lengths
m <- length(lens) %/% 2
idx <- rep(1:m, sapply(1:m, function(.m) sum(lens[(2*.m - 1):(2*.m)])))
if(length(lens) %% 2 != 0){
idx <- c(idx, rep(m + 1, lens[length(lens)]))
sp_idx <- split(idx, idx)
n <- length(sp_idx[[m]])
if(n %/% 2 < length(sp_idx[[m + 1]]))
sp_idx[[m]][(n %/% 2 + 1):n] <- sp_idx[[m + 1]][1]
else
sp_idx[[m]][(n - length(sp_idx[[m + 1]]) + 1):n] <- sp_idx[[m + 1]][1]
idx <- unlist(sp_idx)
}
sp <- split(XXX, idx)
sp
Rui Barradas
Em 25-07-2013 11:40, dennis1991 at gmx.net escreveu:
Hi Rui
once more thank you for your help. But the code does so far not solve the problem because it still treats rows 17-22 (repeated appearance of electrode1) as one single level. However as can be seen by rows 1-3 (or rows 17-19 and rows 20-22) and the order of the length variable (row 1 = 5.7, row 2 = 6.3, row 3 = 6.2) electrode1 consists only of 3 rows. Maybe that was not made absolutely clear by me. As described in my mail before if by chance (or systematically) it happens to be that electrode1 appears right after each other in the table then the code should split it ?half way?.
So idx should not return
[1] 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 3 3 4 4 4
but instead 6 times number 4 at the end
[1] 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4
Do you have any solution?
Gesendet: Mittwoch, 24. Juli 2013 um 23:47 Uhr
Von: "Rui Barradas" <ruipbarradas at sapo.pt>
An: dennis1991 at gmx.net
Cc: r-help at r-project.org
Betreff: Re: Aw: Re: Re: [R] How to split two levels several times?
Hello,
As for the first question, note that in the case you describe, the
resulting list of df's will not be a split of the original, there will
be a duplication in the final 4-1 and 1-3. The following is a hack but
will do it.
lens <- rle(as.character(XXX$electrode))$lengths
m <- length(lens) %/% 2
idx <- rep(1:m, sapply(1:m, function(.m) sum(lens[(2*.m - 1):(2*.m)])))
if(length(lens) %% 2 != 0)
idx <- c(idx, rep(m + 1, lens[length(lens)]))
sp <- split(XXX, idx)
if(length(lens) %% 2 != 0){
idx2 <- sp[[m]]$electrode == sp[[m]]$electrode[nrow(sp[[m]])]
sp[[m + 1]] <- rbind(sp[[m]][idx2, ], sp[[m + 1]])
}
sp
As for the second question, I'm not understanding it, can you post
sample output?
Rui Barradas
Em 24-07-2013 13:58, dennis1991 at gmx.net escreveu:
Hi Rui
the splitting code worked fine. Thanks for your help. Now I realized that the code cannot handle a table with levels that by chance (or systematically) repeatedly appear after each other. For instance this may happen if I need to extract the final two pairs of the table XXX below: electrode4+electrode1 and electrode1+electrode3.
lens <- rle(as.character(XXX$electrode))$lengths
will return 3 2 3 2 6 6 3 and not 3 2 3 2 6 3 3 3 because it counts electrode1 double.
split(XXX, idx) will produce 3 incorrect outputs instead of the required 4.
This will also occur if I have systematic combinations 1-4 after each other for instance in a new table ?XX? below where electrode4 appears twice.
Is there a way to make splitting "half-way" between two of the same levels possible by predefining the length of each individual level? This would make the splitting code more robust. Thanks for advice.
This is the table "XXX"
electrode length
electrode1 5.7
electrode1 6.3
electrode1 6.2
electrode2 11.4
electrode2 9.7
electrode3 14.2
electrode3 14.8
electrode3 12.6
electrode2 11.4
electrode2 9.7
electrode4 17.0
electrode4 16.3
electrode4 17.8
electrode4 18.3
electrode4 16.9
electrode4 18.5
electrode1 5.7
electrode1 6.3
electrode1 6.2
electrode1 5.7
electrode1 6.3
electrode1 6.2
electrode3 14.2
electrode3 14.8
electrode3 12.6
This is a simplified table XX
electrode1
electrode2
electrode1
electrode3
electrode1
electrode4
electrode2
electrode1
electrode2
electrode3
electrode2
electrode4
electrode3
electrode1
electrode3
electrode2
electrode3
electrode4
electrode4
electrode1
electrode4
electrode2
electrode4
electrode3
Gesendet: Dienstag, 23. Juli 2013 um 13:36 Uhr
Von: "Rui Barradas" <ruipbarradas at sapo.pt>
An: dennis1991 at gmx.net
Cc: smartpink111 at yahoo.com, 'r-help' <r-help at r-project.org>
Betreff: Re: Aw: Re: [R] How to split two levels several times?
Hello,
It's better if you keep this on the list, the odds of getting more and
better answers are greater.
As for your new question, try the following.
lens <- rle(as.character(XXX$electrode))$lengths
m <- length(lens) %/% 2
idx <- rep(1:m, sapply(1:m, function(.m) sum(lens[(2*.m - 1):(2*.m)])))
split(XXX, idx)
Hope this helps,
Rui Barradas
Em 23-07-2013 11:41, dennis1991 at gmx.net escreveu:
Hi
this type of splitting works for my specific example. Thanks for your help.
I was not absolutely clear what I generally want. I'm looking for an option that generally permits splitting two joint levels of a table after each other. For instance for the table below I want it to be divided into combinations electrode1-electrode2, electrode3-electrode2, electrode4-electrode1. How should I split this?
This is the table "XXX"
electrode length
electrode1 5.7
electrode1 6.3
electrode1 6.2
electrode2 11.4
electrode2 9.7
electrode3 14.2
electrode3 14.8
electrode3 12.6
electrode2 11.4
electrode2 9.7
electrode4 17.0
electrode4 16.3
electrode4 17.8
electrode4 18.3
electrode4 16.9
electrode4 18.5
electrode1 5.7
electrode1 6.3
electrode1 6.2
Gesendet: Montag, 22. Juli 2013 um 17:53 Uhr
Von: "Rui Barradas" <ruipbarradas at sapo.pt>
An: dennis1991 at gmx.net
Cc: r-help at r-project.org
Betreff: Re: [R] How to split two levels several times?
Hello,
Sorry, I've just realized that your data frame is named 'XXX', not
'dat'. Change that and the rest should work:
idx <- cumsum(c(TRUE, diff(XXX$electrode == "electrode1") > 0))
split(XXX, idx)
Rui Barradas
Em 22-07-2013 16:47, Rui Barradas escreveu:
Hello,
Try the following.
idx <- cumsum(c(TRUE, diff(dat$electrode == "electrode1") > 0))
split(dat, idx)
Hope this helps,
Rui Barradas
Em 22-07-2013 15:09, dennis1991 at gmx.net escreveu:
Hi,
I have a small problem with the function split() and would appreciate
your help.
I have a table called ?XXX? with 2 columns and 49 rows. The 49 rows
belong to 8 different levels (electrode1, ...,electrode8). I want to
split the table always at the row where ?electrode1? starts again so
that I can export 7 individual dataframes (numbered ?dataframe1? to
?dataframe7?) which contain always electrode1 as first level (always
three rows) with the varying number of rows for electrodes2-8 below.
I tried the split function with various setups:
t <- as.factor(XXX$electrode)
dataframeX <- split(XXX, f=(levels=t))
But this doesn?t work. Could you please help. Thank you! Dennis
This is the table "XXX"
electrode length
electrode1 5.7
electrode1 6.3
electrode1 6.2
electrode2 11.4
electrode2 9.7
electrode1 5.7
electrode1 6.3
electrode1 6.2
electrode3 14.2
electrode3 14.8
electrode3 12.6
electrode1 5.7
electrode1 6.3
electrode1 6.2
electrode4 17.0
electrode4 16.3
electrode4 17.8
electrode4 18.3
electrode4 16.9
electrode4 18.5
electrode1 ....
.... ....
electrode5 ....
.... ....
electrode1 ....
electrode6 ....
electrode1 ....
electrode7 ....
electrode1 ....
electrode8 ....