On Jan 17, 2010, at 4:37 PM, Steve Sidney wrote:
Well now I am totally baffled !!!!!!!!!!
Using
sum( !is.na(b[,3])) I get the total of all col 3 except those that are
NA -
Great solves the first problem
What I can't seem to do is use the same logic to count all the 1's in
that
col, which are there before I use the cast with margins.
So it seems to me that somehow is wrong and is the part of my
understanding that's missing.
My guess is that that before using margins and sum in the cast statement
the col is a character type and in order for == 1 to work I need to
convert this to an integer.
Yiu can test your theory with:
sum(as.integer(b[,3]) == 1)
Or you could post some reproducible data using dput ....
--
David.
Hope this helps you to understand the problem.
Regards
Steve
Your help is much appreciated
----- Original Message ----- From: "David Winsemius"
<dwinsemius at comcast.net
To: "Steve Sidney" <sbsidney at mweb.co.za>
Cc: <r-help at r-project.org>
Sent: Sunday, January 17, 2010 7:36 PM
Subject: Re: [R] Help using Cast (Text) Version
On Jan 17, 2010, at 11:56 AM, Steve Sidney wrote:
David
Thanks, I'll try that......but no what I need is the total (1's) for
each of the rows, labelled 1-6 at the top of each col in the table
provided.
Part of my confusion with your request (which remains unaddressed) is
what you mean by "valid". The melt-cast operation has turned a bunch
of
NA's into 0's which are now indistinguishable from the original 0's.
So I
don't see any way that operating on "b" could tell you the numbers you
are asking for. If you were working on the original data, "res", you
might have gotten the column-wise "valid" counts of column 2 with
something like:
sum( !is.na(res[,2]) )
What I guess I am not sure of is how to identify the col after the
melt
and cast.
The cast object represents columns as a list of vectors. The i-th
column
is b[[i]] which could be further referenced as a vector. So the j- th
row
entry for the i-th column would be b[[i]][j].
Steve
----- Original Message ----- From: "David Winsemius"
<dwinsemius at comcast.net
To: "Steve Sidney" <sbsidney at mweb.co.za>
Cc: <r-help at r-project.org>
Sent: Sunday, January 17, 2010 4:39 PM
Subject: Re: [R] Help using Cast (Text) Version
On Jan 17, 2010, at 5:31 AM, Steve Sidney wrote:
Sorry to repeat the meassage, not sure if the HTML version has been
received - Apologies for duplication
Dear list
I am trying to count the no of occurances in a column of a data
frame
and there is missing data identifed by NA.
I am able to melt and cast the data correctly as well as sum the
occurances using margins and sum.
Here are the melt and cast commands
bw = melt(res, id=c("lab","r"), "pf_zbw")
b = cast(bw, lab ~ r, sum, margins = T)
Sample Data (before using sum and margins)
lab 1 2 3 4 5 6
1 4er66 1 NA 1 0 NA 0
2 4gcyi 0 0 1 0 0 0
3 5d3hh 0 0 0 NA 0 0
4 5d3wt 0 0 0 0 0 0
.
. lines deleted to save space
.
69 v3st5 NA NA 1 NA NA NA
70 a22g5 NA 0 NA NA NA NA
71 b5dd3 NA 0 NA NA NA NA
72 g44d2 NA 0 NA NA NA NA
Data after using sum and margins
lab 1 2 3 4 5 6 (all)
1 4er66 1 0 1 0 0 0 2
2 4gcyi 0 0 1 0 0 0 1
3 5d3hh 0 0 0 0 0 0 0
4 5d3wt 0 0 0 0 0 0 0
5 6n44r 0 0 0 0 0 0 0
.
.lines deleted to save space
.
70 a22g5 0 0 0 0 0 0 0
71 b5dd3 0 0 0 0 0 0 0
72 g44d2 0 0 0 0 0 0 0
73 (all) 5 2 4 3 5 7 26
Uisng length just tells me how many total rows there are.
What I need to do is count how many rows there is valid data, in
this
case either a one (1) or a zero (0) in b
I'm guessing that you mean to apply that test to the column in b
labeled "(all)" . If that's the case, then something like (obviously
untested):
sum( b$'(all)' == 1 | b$'(all)' == 0)
I have a report to construct for tomorrow Mon so any help would be
appreciated
Regards
Steve
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
David Winsemius, MD
Heritage Laboratories
West Hartford, CT