replace NAs
I would strongly advise not replacing missing data with unconditional means. Deleting the case is even better. Regards Ross Darnell Brett Magill <freud at starpower.net> writes:
Juan,
Replacing NAs is relatively easy. Nonetheless, I wrote some simple
code to make it even easier for me. You might find it useful. The
first replaces NAs with the mean, the second replaces NAs with a value
you specify. This works for a single vector, you can also use the
apply() function to use it across multiple columns in a data frame or
matrix.
If anyone is interested, I also have code to produce least squares
means by levels of a factor given any number of covariates and code
for classical item analysis (reliability and item characteristics).
replace.na.m<-
function (x){
X<-mean(x,na.rm=TRUE)
ifelse ( is.na(x)=="TRUE",X,x)
}
replace.na.x<-
function(x, value){
ifelse (is.na(x)=="TRUE", value , x)
}
juan pablo perez wrote:
Dear R community: it is possible to replace NA?s in a data frame with zeroes? what should I do? Thanks in advance Juan Pablo
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Ross Darnell School of Health and Rehabilitation Sciences University of Queensland Phone +61 (0)7 3365 6087 Fax +61 (0)7 3365 4754 Email r.darnell at shrs.uq.edu.au -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._