how to convert a data.frame to tree structure object such as dendrogram
Of course, R's recursive lists **are** trees. (Some expert may rap my knuckles here, but ... close enough?) -- Bert
On Mon, Mar 11, 2013 at 1:12 PM, MacQueen, Don <macqueen1 at llnl.gov> wrote:
You will have to decide what R data structure is a "tree structure". But maybe this will get you started:
foo <- data.frame(x=c('A','A','B','B'), y=c('Ab','Ac','Ba','Bd'))
split(foo$y, foo$x)
$A [1] "Ab" "Ac" $B [1] "Ba" "Bd" I suppose it is at least a little bit tree-like. -- Don MacQueen Lawrence Livermore National Laboratory 7000 East Ave., L-627 Livermore, CA 94550 925-423-1062 On 3/10/13 9:19 PM, "Not To Miss" <not.to.miss at gmail.com> wrote:
I have a data.frame object like:
data.frame(x=c('A','A','B','B'), y=c('Ab','Ac','Ba','Bd'))
x y
1 A Ab
2 A Ac
3 B Ba
4 B Bd
how could I create a tree structure object like this:
|---Ab
A---|
_| |---Ac
|
| |---Ba
B---|
|---Bb
Thanks,
Zech
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______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Bert Gunter Genentech Nonclinical Biostatistics Internal Contact Info: Phone: 467-7374 Website: http://pharmadevelopment.roche.com/index/pdb/pdb-functional-groups/pdb-biostatistics/pdb-ncb-home.htm