pattern matching
"$" has a special meaning (end-of-string) in regular expressions, so you can either escape it with "\\" or not use regular expressions in regexpr():
regexpr("\\$", "x$Expensive")
[1] 2 attr(,"match.length") [1] 1 attr(,"useBytes") [1] TRUE
regexpr("$", "x$Expensive", fixed=TRUE)
[1] 2 attr(,"match.length") [1] 1 attr(,"useBytes") [1] TRUE Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com
-----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Data Analytics Corp. Sent: Monday, January 07, 2013 1:22 PM To: r-help at R-project.org Subject: [R] pattern matching Hi, I have a simple question. Suppose I have a string "x$Expensive". I want to find the position of the $ in this string; i.e., I want a function that returns 2. I tried grep, regexpr, etc with no luck, unless I'm just using them incorrectly. Any suggestions? Thanks, Walt
________________________ Walter R. Paczkowski, Ph.D. Data Analytics Corp. 44 Hamilton Lane Plainsboro, NJ 08536 ________________________ (V) 609-936-8999 (F) 609-936-3733 walt at dataanalyticscorp.com www.dataanalyticscorp.com ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.