barplot: legend: two rows

Hello,

I solved my problem with the uneven numbers of legend elements, which
should be put into more than one rows, in the following way:

I added another legend element which is empty ("") and is filled with
"white":

legend(0,-1.4,xjust=0,ncol=3,legend=c(colnames(dat)[-1],""),fill=c("navyblue","steelblue4","steelblue2","lightsteelblue3","lightsteelblue1","white"),bty="n",border="white",cex=1.2)

Not quite such a nice way, but it works, anyway.

Marion

2012/5/11 Marion Wenty<marion.wenty at gmail.com>

Hello,

thank you very much for your answers. Using the command ncol worked in my
special case, if I have got a legend with 4 elements, but with 5 it doesn't
work. I am using two functions which I had created and checked what might
be the difference, so that the second one doesn't work, but I couldn't find
out what the problem is. So I am including the text of my .csv files and my
functions:


My .csv file "abb8a" looks like this:

;sehr gut;eher gut;eher nicht gut;nicht gut
Kontakt mit der Schule;46;49;4;1
Die richtige Wahl;32;58;8;2


mw_g_4stap<-function(pfad="F:/04 Archiv/04 Programme/19
R_Syntaxe/Grafiken_Funktionen",abb="abb8a")
{
   setwd(pfad)
   postscript(file=paste(abb,".eps",sep=""))
   dat<-read.csv2(paste(abb,".csv",sep=""),header=T,check.names=F)
   dat1<-t(as.matrix(dat[,2:5],nrow=2))
   colnames(dat1)<-dat[,1]
   zehn<-seq(10,100,10)
   xmax<-max(dat1)
   ind<-min(which(zehn>=xmax))
   ticks<-seq(0,100,10)
   par(las=1)
   par(mar=c(5.9,4.5+0.3529412*(max(nchar(colnames(dat1)))-1),1,1))

barplot(dat1,width=0.61,horiz=T,col=c("steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),border="NA",axes=F,beside=F,xlim=c(0,100),cex.names=1.2,ylim=c(0,10))
   par(xpd=TRUE)
   abline(v = seq(10, 100, by = 10), col = "white")
   par(xpd=F)
   axis(1,at=ticks,las=1,labels=paste(ticks,"%",sep=""))
   par(xpd=TRUE)

legend(0,-1.4,xjust=0,ncol=2,legend=colnames(dat)[-1],fill=c("steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),bty="n",border="white",cex=1.2)
   par(xpd=FALSE)
   dev.off()
}
mw_g_4stap()

###

My .csv file "probe8_5" looks like this:

;stimme zu;stimme zu;stimme zu;stimme zu;stimme zu
Eltern konnten mir beim ler;23;70;1;1;5
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50
leichte Ent;20;10;10;10;50


mw_g_5stap<-function(pfad="F:/04 Archiv/04 Programme/19
R_Syntaxe/Grafiken_Funktionen",abb="probe8_5")
{
   setwd(pfad)
   postscript(file=paste(abb,".eps",sep=""))
   dat<-read.csv2(paste(abb,".csv",sep=""),header=T,check.names=F)
   dat1<-t(as.matrix(dat[,2:6],nrow=2))
   dat1
   colnames(dat1)<-dat[,1]
   dat1
   zehn<-seq(10,100,10)
   xmax<-max(dat1)
   ind<-min(which(zehn>=xmax))
   ticks<-seq(0,100,10)
   par(las=1)
   par(mar=c(5,4.5+0.3529412*(max(nchar(colnames(dat1)))-1),1,1))

barplot(dat1,width=0.61,horiz=T,col=c("navyblue","steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),border="NA",axes=F,beside=F,xlim=c(0,100),cex.names=1.2,ylim=c(0,10))
   par(xpd=TRUE)
   abline(v = seq(10, 100, by = 10), col = "white")
   par(xpd=F)
   axis(1,at=ticks,las=1,labels=paste(ticks,"%",sep=""))
   par(xpd=TRUE)

legend(0,-1.4,xjust=0,ncol=3,legend=colnames(dat)[-1],fill=c("navyblue","steelblue4","steelblue2","lightsteelblue3","lightsteelblue1"),bty="n",border="white",cex=1.2)
   dev.off()
}
mw_g_5stap()

###

The first function works but the second one doesn't.

Does anyone know why?

Thank you very much for your help in advance!!

Marion



2012/5/9 Uwe Ligges<ligges at statistik.tu-dortmund.de>

On 09.05.2012 13:23, Marion Wenty wrote:

dear r-helpers,

i have got another question:

i am using the functions

par(xpd=T)
legend

to create a legend below the x-axis. i used the parameter horiz=T.

now i would like to put the elements of the legend in two rows:

e.g. if my legend has got 5 elements, i would like 3 elements in one row
and the last two elements in the next row.

does anyone know how to do that?

Example:

bp<- barplot(1)
par(xpd = TRUE)
legend(bp, 0, xjust=0.5, legend=letters[1:5], lwd=1:5, ncol=3)

Uwe Ligges


  thank you very much for your help in advance!

marion

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