Summarizing each row into a frequency table
Tena koe Daren One alternative: apply(m, 1, function(x) 100*summary(factor(x, levels=-1:1))/length(x[!is.na(x)])) Doubtless there are others. HTH .... Peter Alspach
-----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Daren Tan Sent: Tuesday, 24 March 2009 1:46 p.m. To: r-help at r-project.org Subject: [R] Summarizing each row into a frequency table I have a matrix containing -1, 0, 1, however certain rows will not have all 3 numbers. I have written some codes to compute the frequency table of how many -1s, 0s, 1s per row, but it is very ugly and not efficient if there are more than 3 numbers. Please suggest. m <- rbind(sample(0:1, replace=T, 10), sample(-1:1, replace=T, 10)) m.table <- t(apply(m, 1, function(x) c(sum(x==-1, na.rm=T), sum(x==0, na.rm=T), sum(x==1, na.rm=T)) )) m.table <- prop.table(m.table, 1)*100 colnames(m.table) <- -1:1
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