Message-ID: <CAM_vjunXq+La8qRT-Z8YOiub+JYfSMboX95Tiwf6gfgVetc2tw@mail.gmail.com>
Date: 2011-10-05T19:14:54Z
From: Sarah Goslee
Subject: dynamically creating functions in r
In-Reply-To: <1317826645792-3874767.post@n4.nabble.com>
Hi,
On Wed, Oct 5, 2011 at 10:57 AM, honeyoak <honeyoak at gmail.com> wrote:
> it is possible to dynamically create functions in R using lists? what I want
> to do is something like this:
>
> ? ? ?a = list()
> ? ? ?for (i in 1:10) a[[i]] = function(seed = i) runif(seed)
>
> so that when I call a[i] I get random draws 1,2,....i unfortunately R only
> uses the last i .
I'm not sure I understand what you want. Do you want to set a new seed for
the random number generator, or do you want a random vector of length i
each time?
If the former, I'm not sure why you'd want to do that, but your choice
of variable
names makes me wonder.
If the latter, you just need a bit of clean-up.
a <- list()
for (i in 1:10) {
a[[i]] <- runif(i)
}
But that's not dynamically creating a function, so maybe I'm missing the point.
> I would also like to know if there is a run-all function
> without explicitly looping or using lapply. for example if I have a list 'b'
> of functions if I called
>
> ? ? ?run-all(b)
>
> all the functions in list 'b' would be run
>
> thanks.
What's wrong with lapply? I think we need to know more about what you're
trying to do. You might also want to look at do.call().
Sarah
--
Sarah Goslee
http://www.functionaldiversity.org