expressions (nesting, substitution, 2-stage evaluation)
Yes, plotmath contains expressions. The example produced in ?plotmath is not as complex as the example I provided. bquote and substitute allow substitutions of variables ... but what I need to be able to do is substitute an expression... and that is the magic I'm looking for. thanks, Daryl
On 2/27/14 3:17 PM, Bert Gunter wrote:
?plotmath -- Bert Bert Gunter Genentech Nonclinical Biostatistics (650) 467-7374 "Data is not information. Information is not knowledge. And knowledge is certainly not wisdom." H. Gilbert Welch On Thu, Feb 27, 2014 at 2:58 PM, Daryl Morris <darylm at uw.edu> wrote:
Hi,
I have a function which generates many plots. To keep it simple, let's say
I want to set the main title based on where we are in nested loops.
So, something like
vectorA = c("a","b","c")
vectorB = c("a","b","c")
for(ii in vectorA) { for(jj in vectorB) {
plot(0:1,0:1)
title(main = paste(ii,jj))
}
that part is easy! The question is what if I wanted vectorA to be an
expression?
I'd like to be able to set vectorA =
c(expression(paste("TNF-",alpha)),expression(paste("IFN-",gamma))), and have
the plot title show the greek letters.
Obviously, in the for-loop I could build the expression all at once, but
there are lots of programmatic reasons I'd like to be able to have this
program structure. Is there a solution which modifies either/both (1) the
setting of main in the loop (2) how I define the vector outside of the loop?
thanks, Daryl
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