HI,
You can also try this as a function:
fun1<-function(x){
B<-gsub("percent{0,1}\\s\\((.*)\\)","\\1",x)
C<-gsub("(.*)/(.*)","\\1 0 0 \\2", gsub("(.*)/(.*)/(.*)","\\1 \\2 0 \\3", gsub("(.*)/(.*)/(.*)/(.*)","\\1 \\2 \\3 \\4",B)))
dat1<-data.frame(do.call(rbind,strsplit(C," ")))
colnames(dat1)<-paste0("A",1:4)
dat1
}
?fun1(A)
#? A1 A2 A3 A4
#1 10 20? 0 30
#2 40? 0? 0 20
#3 60 10 10? 5
#4 80? 0? 0 10
A.K.
----- Original Message -----
From: Rui Barradas <ruipbarradas at sapo.pt>
To: Sapana Lohani <lohani.sapana at ymail.com>
Cc: r-help <r-help at r-project.org>
Sent: Sunday, September 2, 2012 1:05 PM
Subject: Re: [R] splits with 0s in middle columns
Hello,
You don't need a new function, what you need is to prepare your data in
such a way that the function can process it.
A <- c("percent (10/20/30)", "percent (40/20)", "percent (60/10/10/5)",
"percent (80/10)")
B <- gsub("\\(|\\)|percent| ", "", A)
fun(B)
Also, please use dput to post the data examples,
dput(A)
c("percent (10/20/30)", "percent (40/20)", "percent (60/10/10/5)",
"percent (80/10)")
Then copy&paste in your post.
Rui Barradas
Em 02-09-2012 04:22, Sapana Lohani escreveu:
Dear Rui,
The new code works fine for what I wanted. I have another similar column but it looks like
A
percent (10/20/30)
percent (40/20)
percent (60/10/10/5)
percent (80/10)
I want a similar split but delete the percent in the front. The output should look like
A1 A2 A3 A4
10 20 0 30
40 0 0 20
60 10 10 5
80 0 0 10
Could you please make the small change in the code that you gave me. It must be a small edition but I could not figure that out. FYI the code that worked was
fun <- function(X){
? ? ? xname <- deparse(substitute(X))
? ? ? s <- strsplit(X, "/")
? ? ? n <- max(sapply(s, length))
? ? ? tmp <- numeric(n)
? ? ? f <- function(x){
? ? ? ? ? x <- as.numeric(x)
? ? ? ? ? m <- length(x)
? ? ? ? ? if(m > 1){
? ? ? ? ? ? ? tmp[n] <- x[m]
? ? ? ? ? ? ? tmp[seq_len(m - 1)] <- x[seq_len(m - 1)]
? ? ? ? ? }else tmp[1] <- x
? ? ? ? ? tmp
? ? ? }
? ? ? res <- do.call(rbind, lapply(s, f))
? ? ? colnames(res) <- paste(xname, seq_along(s), sep = "")
? ? ? data.frame(res)
}
fun(A)
Thank you so very much.